Answer:

Explanation:
1. Calculate the adult life
If the elephant is an adult from its 10th birthday until the day before its 56th birthday, its
Adult life = 55 - 10 + 1 = 46 yr
2. Convert years to days

3. Convert days to pounds of feed

4. Convert pounds to kilograms and megagrams

Note: The answer can have only two significant figures because that is all you gave for age of the elephant.
Answer:
cerium (iii) sulfate is less soluble
Their lungs would try to expand to about 4 timed the normal volume which would force air into the various body tissues. this can cause a lung expansion injury and it could case air embolism. Air embolism is when air bubbles get trapped in blood vessels. This can lead to a blockage which will could be fatal.
Answer:
<h2>1.38 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula

where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have

We have the final answer as
<h3>1.38 moles</h3>
Hope this helps you