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Nataliya [291]
3 years ago
5

Which structure diagram completes the table of physical structures of the main functional groups?

Chemistry
2 answers:
azamat3 years ago
7 0

Answer:

B on edge 2020

Explanation:

expeople1 [14]3 years ago
4 0
<h3><u>Answer;</u></h3>

R'

. |

C = O

. |

R

<h3><u>Explanation; </u></h3>
  • Ketones are byproducts of the breakdown of fatty acids.<u> They are organic compounds with the structure R(C=O)R', where R and R' can be a variety of carbon-containing substituents.</u>
  • Like aldehydes ketones contain a carbonyl group that is a carbon oxygen double bond.

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Decide whether the property measured was a chemical or physical property of X, if you can. If you don’t have enough information
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<u><em>See attachment for explanations.</em></u>

Explanation:

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2 years ago
Research how different fossil fuels compare in terms of the amount of carbon dioxide released per kWh of energy. How much carbon
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Answer:

About 19.64 pounds of carbon dioxide are produced from burning a gallon of gasoline. On the other hand, 22.38 pounds of carbon dioxide are produced from burning a gallon of diesel. So, different fossil fuels will give different amounts of carbon dioxide to be released.

Explanation:

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3 years ago
Matthew records the temperature outside for one day. From 10:00 a.m. to 12:00 p.m., the temperature rises 4°C. From 12:00 p.m. t
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3 years ago
125.0 g of an unknown substance is heated to 97.0°C. It is then placed in a calorimeter than contains 250g of water with an init
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4 years ago
Read 2 more answers
10mL volume of 75mM EtOH is necessary for an experiment. What volumes of 1M EtOH and water should be mixed to obtain the working
kenny6666 [7]

Answer: Volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration.

Explanation:

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = molarity of stock solution = 1M

V_1 = volume of stock solution = ?

C_2 = molarity of diluted solution = 0.075 M    (1mM=0.001M)

V_2 = volume of diluted solution = 10 ml

Putting in the values we get:

1M\times V_1=0.075M\times 10ml

V_1=0.75ml

Thus 0.75 ml of 1M EtOH is taken and (10-0.75)ml = 9.25 ml of water is added to make the volume 10ml.

Therefore, volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration

3 0
3 years ago
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