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soldier1979 [14.2K]
3 years ago
12

If glucose is the sole energy source, what fraction of the carbon dioxide exhaled by animals is generated only by the reactions

involved in oxidation of pyruvate to acetyl coa?
Chemistry
2 answers:
White raven [17]3 years ago
7 0

We have to know what fraction of the carbon dioxide exhaled by animals is generated only by the reactions involved in oxidation of pyruvate to acetyl coa.

The fraction is: 1 CO₂ per puruvate molecule.

Pyruvate oxidation takes place in the mitochondrial matrix, before chemical reactions begins, pyruvate enters the mitochondrion crossing the inner membrane and arriving at the matrix.

Oxidation of pyruvate results acetyl coenzyme A after release of one molecule of CO₂.


Flauer [41]3 years ago
3 0

Answer:

1/3

Explanation:

Pyruvate is produced by the glycolysis in cytoplasm. The oxidation of pyruvate takes place in mitochondrial matrix.  

Pyruvate is converted to acetyl-CoA in the reaction given below:

Pyruvate + NAD⁺ + CoA-SH ⇒ acetyl-CoA + NADH + CO₂

<u> 1 molecule of carbon dioxide is eliminated from 1 molecule of pyruvate.</u>

<u>Also, </u>

<u>2 molecules of carbon dioxide is eliminated from 2 molecules of pyruvate (as glucose on glycolysis yields 2 molecules of pyruvate).</u>

Also, acetyl-CoA further goes into the citric acid cycle and produces 2 molecules of carbon dioxide.

<u>Thus pyruvate produces total 3 molecules of CO₂  and hence glucose produces 6 molecules of CO₂ (as glucose on glycolysis yields 2 molecules of pyruvate)</u>

Thus,

<u>Fraction = 2/6 = 1/3</u>

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Answer:

             70.15 cm³

Solution:

Data Given;

                  Mass  =  55 g

                  Density  =  0.784 g.cm⁻³

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                  Volume  =  ?

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Putting values,

                  Volume  =  55 g ÷ 0.784 g.cm⁻³

                  Volume = 70.15 cm³

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3 years ago
Answer the following questions for H2CrO4:
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If this molecule is one half of a buffer, then the formula of the second half of the buffer is M2CrO4 where M is a univalent metal.

<h3>What is a strong acid?</h3>

A weak acid is one that is able to ionize completely in solution. The acid called chromic acid H2CrO4 is not  able to ionize completely in solution.

We know that a buffer is composed of a weak acid and its salt or a weak base and its salt hence if the acid H2CrO4 is present in a buffer then the other half must be  salt of the acid.

If this molecule is one half of a buffer, then the formula of the second half of the buffer is M2CrO4 where M is a univalent metal.

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Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that
iragen [17]

Answer:

108.43 grams KNO₃

Explanation:

To solve this problem we use the formula:

  • ΔT = Kf * b * i

Where

  • ΔT is the temperature difference (14.5 K)
  • Kf is the cryoscopic constant (1.86 K·m⁻¹)
  • b is the molality of the solution (moles KNO₃ per kg of water)
  • and<em> i</em> is the van't Hoff factor (2 for KNO₃)

We <u>solve for b</u>:

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Using the given volume of water and its density (aprx. 1 g/mL) we <u>calculate the necessary moles of KNO₃</u>:

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