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soldier1979 [14.2K]
2 years ago
12

If glucose is the sole energy source, what fraction of the carbon dioxide exhaled by animals is generated only by the reactions

involved in oxidation of pyruvate to acetyl coa?
Chemistry
2 answers:
White raven [17]2 years ago
7 0

We have to know what fraction of the carbon dioxide exhaled by animals is generated only by the reactions involved in oxidation of pyruvate to acetyl coa.

The fraction is: 1 CO₂ per puruvate molecule.

Pyruvate oxidation takes place in the mitochondrial matrix, before chemical reactions begins, pyruvate enters the mitochondrion crossing the inner membrane and arriving at the matrix.

Oxidation of pyruvate results acetyl coenzyme A after release of one molecule of CO₂.


Flauer [41]2 years ago
3 0

Answer:

1/3

Explanation:

Pyruvate is produced by the glycolysis in cytoplasm. The oxidation of pyruvate takes place in mitochondrial matrix.  

Pyruvate is converted to acetyl-CoA in the reaction given below:

Pyruvate + NAD⁺ + CoA-SH ⇒ acetyl-CoA + NADH + CO₂

<u> 1 molecule of carbon dioxide is eliminated from 1 molecule of pyruvate.</u>

<u>Also, </u>

<u>2 molecules of carbon dioxide is eliminated from 2 molecules of pyruvate (as glucose on glycolysis yields 2 molecules of pyruvate).</u>

Also, acetyl-CoA further goes into the citric acid cycle and produces 2 molecules of carbon dioxide.

<u>Thus pyruvate produces total 3 molecules of CO₂  and hence glucose produces 6 molecules of CO₂ (as glucose on glycolysis yields 2 molecules of pyruvate)</u>

Thus,

<u>Fraction = 2/6 = 1/3</u>

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If volumes are additive and 253 mL of 0.19 M potassium bromide is mixed with 441 mL of a potassium dichromate solution to give a
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1000 mL solution ----- 0.19 moles of KBr

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0.587124 final K+ moles - 0.04807 K+ moles from KBr = 0.539054 K+ moles from K2Cr2O7

If we go back and take a look a the chemical reactions, we can see that 1 mole of K2Cr2O7 dissociates into 2 moles of K+ ions, so:

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441 mL ----- 0.269527 K2Cr2O7 moles

1000 mL ----- x = 0.6112 K2Cr2O7 moles = 0.6112 M

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