Full Question:
A flask containing 420 Ml of 0.450 M HBr was accidentally knocked to the floor.?
How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation?
2HBr(aq)+K2CO3(aq) ---> 2KBr(aq) + CO1(g) + H2O(l)
Answer:
13.1 g K2CO3 required to neutralize spill
Explanation:
2HBr(aq) + K2CO3(aq) → 2KBr(aq) + CO2(g) + H2O(l)
Number of moles = Volume * Molar Concentration
moles HBr= 0.42L x .45 M= 0.189 moles HBr
From the stoichiometry of the reaction;
1 mole of K2CO3 reacts with 2 moles of HBr
1 mole = 2 mole
x mole = 0.189
x = 0.189 / 2 = 0.0945 moles
Mass = Number of moles * Molar mass
Mass = 0.0945 * 138.21 = 13.1 g
Answer:
First iron fillings are separated by using a magnet. magnet attracts iron fillings, thus iron fillings get separated. then dissolve aluminium powder and sugar in water as aluminium is insoluble in water it will become a filtrate.
Explanation:
To determine whether our equations are balanced, we must write the elements on the products side and also the reactants side. If the amount of the elements (coefficients and subscripts) are equal on both sides, we have a balanced equation.
Lets try (A)
2NaCl + H₂SO₄ → HCl + NaSO₄
Na=2 Na=1
Cl=2 Cl=1
H=2 H=1
Na=2 Na=1
S=1 S=1
O=4 O=4
Most of the elements here are not equal for both sides, therefore, A is not the answer.
Lets try (B)
2Na + S → 2NaS
Na=2 Na=2
S=1 S=2
This is a wrong answer because S is not equal on both sides. B is a wrong answer.
Lets try (C)
KOH + H2SO4 → KHSO4 + H2O
K=1 K=1
O= 1 O=1
H=1 H=1
H=2 H=2
S=1 S=1
O=4 O=4
THIS IS A BALANCED EQUATION!!!! ALL ELEMENTS ARE EQUAL ON BOTH SIDES!!!
Since we already know that C is our answer, we have no need to check D. Also, D is incorrect because N has 1 on reactants side, and 2 on the other. Therefore, we automatically know that D is wrong.
FINAL ANSWER: C IS OUR ANSWER, IT IS A BALANCED EQUATION. :)
