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3 years ago

7

Imagine that instead of balls, you were rolling positively charged ions of the same element).

1 answer:

Ghella [55]3 years ago

8 0

The ion with a +3 charge would be deflected the most by the magnet because it has the strongest positive charge therefore it will be the one being the most repelled. and the ion that would be deflected the least would be the ion with a +1 charge because it has the least amount of charge so the magnet will still repel it but just not as much as it will repel the ion with a +3 charge.

hope that helps

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When 3.4 moles of hydrogen gas react with excess oxygen how many moles of water will be produced

s344n2d4d5 [400]

1. start with balanced equation.
2 H2(g) + O2(g<span>) </span><span> 2 H</span>2O(g<span>)
</span>
2. Use stoichiometry
(3.4moles of H)(2moles of H2O/2moles of H)
The moles of H will cancel, leaving you with moles of H2O.
The answer is 3.4 moles of H2O

6 0

4 years ago

A 4.80g piece of magnesium (Mg) displaces 2.76mL of water when it is placed in a graduated cylinder. What is the density of magn

AnnZ [28]

Answer:

<h2>1.74 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{4.80}{2.76} \\ = 1.73913...$

We have the final answer as

<h3>1.74 g/mL</h3>

Hope this helps you

8 0

3 years ago

The currently accepted model of the atom includes an electron cloud.<br> A. True<br> B. False

natulia [17]

Answer:

True

Explanation:

4 0

3 years ago

Read 2 more answers

A sample of propane (C3H8) is placed in a closed vessel together with an amount of O2 that is 3 times the amount needed to compl

Aneli [31]

Answer:

final mole fraction of O₂ = 58.84% , CO₂ = 17.64% , H₂O = 23.52% .

final partial pressure of O₂ = 2.942 atm , CO₂ = 0.882 atm , H₂O = 1.176 atm .

Explanation:

Assuming that propane is present as a gas , and also that the combustion is complete:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

then taking as a reference propane sample= 1 mol , then

initial moles of O₂ = 3* 5 moles = 15 moles

final moles of O₂= 3* 5 moles - 5 moles = 10 moles

final moles of CO₂ = 3 moles

final moles of H₂O = 4 moles

total number of moles = 10 + 3 + 4 = 17 moles

final mole fraction of O₂ = 10/17 = 0.5884 = 58.84%

final mole fraction of CO₂ = 3/17 = 0.1764 = 17.64%

final mole fraction of H₂O = 4/17 = 0.2352 = 23.52%

From Dalton's law for ideal gases , the partial pressure p=P*x then

final partial pressure of O₂ = 5 atm * 10/17 = 2.942 atm

final partial pressure of CO₂ = 5 atm * 3/17 = 0.882 atm

final partial pressure of H₂O = 5 atm * 1/17 = 1.176 atm

4 0

3 years ago

Read 2 more answers

When the temperature of a sample of pure water is raised above 25 °C,(1)the hydronium ion concentration will be greater than the

Ludmilka [50]

Answer:

The correct answer is option 3.

Explanation:

$H_2O\rightleftharpoons H^++OH^-$

The expression of $K_w$ is given by :

$K_w=[H^+][OH^-]$

$K_w\propto [H^+]$

$K_w\propto [OH^-]$

Rise in temperature will result in more dissociation of water molecules into hydrogen ions and hydroxide ions.

With an increase in concentration of hydrogen ions and hydroxide ions value of $K_w$ will also increase.

5 0

4 years ago