1.679 × 10²³ g of PbO₂ is present in 4.23×10⁴⁴ particles of PbO₂.
<u>Explanation:</u>
First the number of particles is converted into moles by dividing it by the Avogadro's number and then moles multiplied by the molar mass, we will get the mass of PbO₂ in grams.
4.23×10⁴⁴/ 6.022×10²³ = 7.02×10²⁰ moles
Now we have to multiply this by the molar mass of PbO₂, that is 239.2 g/mol, we will get the mass in grams.
7.02×10²⁰ moles × 239.2 g/mol = 1.679 × 10²³ g of PbO₂
2. I believe it would be two but then again this is an incomplete answer so it is not two. It's probably going to be 3. Or 1. Because I took this test before a while back and I'm almost a 100% sure it's 1 or 3. Hope this helps slightly!
The cruise control on a car is an example of a control loop.
