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bulgar [2K]
2 years ago
13

Teeth and long bones are good indicators of age in children; ribs and joints are better for adults.

Chemistry
2 answers:
attashe74 [19]2 years ago
7 0

Answer:

True

Explanation:

Luba_88 [7]2 years ago
4 0

The answer is True not False

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Marcus measured the masses and volumes of samples of four different substances, and he calculated their densities. The table sho
Zina [86]

<u>Given:</u>

Calculated density values-

Aluminum = 2.7 g/cm3

Copper = 9.0 g/cm3

Iron = 7.9 g/cm3

Titanium = 4.8 g/cm3

Unknown sample mass = 9.5 g

Sample volume = 2.1 cm3

<u>To determine:</u>

The identity of the unknown sample

<u>Explanation:</u>

'Density' is a physical parameter which can be used to identify the nature of the unknown substance.

Density = Mass/Volume

For the unknown sample

Density = 9.5 g/2.1 cm3 = 4.52 g/cm3

This matches closely with the calculated density of titanium

Ans: The unknown substance is made of titanium

4 0
2 years ago
“NH4VO3” is a... <br><br> Symbol <br><br><br> Name <br><br><br> Chemical formula
shepuryov [24]

Answer:

its a chemical formula, it has numbers and symbols

3 0
3 years ago
Read 2 more answers
In the reaction K2CrO4 (aq) + PbCl2 (aq) 2KCl (aq) + PbCrO4(s), how many grams of PbCrO4 will precipitate out from the reaction
tankabanditka [31]
The answer is 24 grams                       
6 0
2 years ago
How many milliliters of 0.100 m naoh are required to neutralize 9.00 ml of 0.0500 m hcl?
BabaBlast [244]
V  ( NaOH ) = mL ?

M ( NaOH ) = 0.100 M

V ( HCl ) = 9.00 mL / 1000 => 0.009 L

M ( HCl ) = 0.0500 M

number of moles HCl:

n = M x V

n = 0.009 x 0.0500 => 0.00045 moles HCl

mole ratio:

<span>HCl + NaOH = NaCl + H2O
</span>
 1 mole HCl ---------------- 1 mole NaOH
 0.00045 moles HCl ----- ??

0.00045 x 1 / 1 => 0.00045 moles of NaOH

M = n / V

0.100 = 0.00045 / V

V = 0.00045 / 0.100

V = 0.0045 L

1 L ------------ 1000 mL
0.0045 L ----- ??

0.0045 x 1000 / 1 => 4.5 mL of NaOH



6 0
3 years ago
5. Students hypothesize that temperature is a limiting factor for the germination of seeds. They carry out an experiment to
Lelechka [254]

Answer:

keep adding to on each term its quit simple

8 0
2 years ago
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