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strojnjashka [21]
3 years ago
12

Round your answers to one decimal place.this parallel circuit has two resistors at 15 and 40 ohms. what is the total resistance?

ωif there is a 12 v battery in the circuit, what would the approximate current be? a
Physics
2 answers:
lubasha [3.4K]3 years ago
4 0
1) The equivalent resistance of two resistors in parallel is given by:
\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}
so in our problem we have
\frac{1}{R_{eq}} =  \frac{1}{15 \Omega}+ \frac{1}{40 \Omega}=0.092 \Omega^{-1}
and the equivalent resistance is
R_{eq} =  \frac{1}{0.092 \Omega^{-1}}=10.9 \Omega

2) If we have a battery of 12 V connected to the circuit, the current in the circuit will be given by Ohm's law, therefore:
I= \frac{V}{R_{eq}}= \frac{12 V}{10.9 \Omega}=1.1 A
Ronch [10]3 years ago
4 0

10.9Ohms

1.1A i did it on Edge and it was correct

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\theta = 49.56 degree

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t = 3.98 s

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3 years ago
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Vector A has a magnitude of 50 units and points in the positive x direction. A second vector, B , has a magnitude of 120 units a
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v_x = v cos \theta

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B_x = B cos \theta_B = (120) cos (-70^{\circ})=41

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B) Vector B

Instead, the y-component of a vector can be found by using the formula

v_y = v sin \theta

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