Answer:
230.4 s
Explanation:
The speed of car A is

and the distance travelled is

so the time taken for car A is

The speed of car B is

and the distance travelled is

so the time taken for car B is

So the difference in time is

Which corresponds to

so car B arrived 230.4 s before car A.
Answer:
Initial velocity, U = 28.73m/s
Explanation:
Given the following data;
Final velocity, V = 35m/s
Acceleration, a = 5m/s²
Distance, S = 40m
To find the initial velocity (U), we would use the third equation of motion.
V² = U² + 2aS
Where;
V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
S represents the displacement measured in meters.
Substituting into the equation, we have;
35² = U + 2*5*40
1225 = U² + 400
U² = 1225 - 400
U² = 825
Taking the square root of both sides, we have;
Initial velocity, U = 28.73m/s
Answer: weight on Jupiter = 869.75 N
mass on Earth = mass on Jupiter = 35.5 Kg
Explanation:
W = mg
W = weight
m = mass
g = gravitational acceleration [ on the Earth, g₁ = 9,8 N/kg ]
On the Earth,
G₁ = m x g₁ = 347,9 N
On the Jupiter,
G₂ = mg₂
mass on the Earth = mass on the Jupiter !
m = G₁ : g = 347.9 N : 9,8 N/kg = 35.5 kg
G2 : G1 = 2.5
G₂ = 2,5 G₁ = 2,5 x 347.9 N = 869,75 N
<u>Answer:</u> The ball is travelling with a speed of 5.5 m/s after hitting the <u>bottle.</u>
<u>Explanation:</u>
To calculate the speed of ball after the collision, we use the equation of law of conservation of momentum, which is given by:

where,
are the mass, initial velocity and final velocity of ball.
are the mass, initial velocity and final velocity of bottle.
We are given:

Putting values in above equation, we get:

Hence, the ball is travelling with a speed of 5.5 m/s after hitting the bottle.