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3 years ago

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A force of 1.2 N is applied to an object of mass 1.5 kg. It accelerates at 0.50m/s . Determine

2 answers:

Taya2010 [7]3 years ago

8 0

Answer:

0.03

Explanation:

Juliette [100K]3 years ago

3 0

Answer: Check the pic

Explanation:

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An astronaut has left the International Space Station to test a new space scooter. Her partner measures the following velocity c

KiRa [710]

Acceleration can be defined as the change of speed in an instant of time, that is

$a = \frac{v_f-v_i}{\Delta t}$

Here,

$v_f =$ Final velocity

$v_i =$ Initial velocity

$\Delta t =$ Change in time

From this expression we will calculate the requested values replacing the variables in each of the given terms

PART A) The values under this condition are:

$v_f = 5.3m/s$

$v_i = 15m/s$

$\Delta t = 10.4s$

Replacing,

$a = \frac{5.3m/s-(15m/s)}{10.4s}$

$a = -0.93m/s^2$

PART B ) The values under this condition are:

$v_f = -15m/s$

$v_i = -5.3m/s$

$\Delta t = 10.4$

Replacing,

$a = \frac{-(15m/s)-(-5.3m/s)}{10.4s}$

$a = -0.93m/s^2$

Therefore the acceleration in the second time interval is $-0.93m/s^2$

PART C) The values under this condition are:

$v_f = -15m/s$

$v_i = 15m/s$

$\Delta t = 10.4$

Replacing,

$a = \frac{-15m/s-(15m/s)}{10.4s}$

$a = -2.9m/s^2$

6 0

3 years ago

Match the correct center and scale factor to each figure.

34kurt

Answer:

Image

Explanation:

I looked at the graph and assumed answers

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3 years ago

Reasons why inductors opposes charges passing through it<br>

saul85 [17]

Answer:

é isso daí msm

Explanation:

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3 years ago

A pulley with a radius of 3.0 cm and a rotational inertia of 4.5 x 10–3 kg∙m2 is suspended from the ceiling. A rope passes over

vekshin1

Answer:

22J

Explanation:

Given :

radius 'r'= 3cm

rotational inertia 'I'=4.5 x $10^{-3}$ kgm²

mass on one side of rope ' $m_{1$ '= 2kg

mass on other side of rope' $m_{2$ ' =4kg

velocity'v' of mass $m_{2$ ' = 2m/s

Angular velocity of the pulley is given by

‎ω = v /r => 2/ 3x $10^{-2$

‎ω = 66.67 rad/s

For the rotating body, we have

KE = $\frac{1}{2}$ I ω²

$KE_p = \frac{1}{2} (4.5 *10^{-3} )(66.67^{2} )$

$KE_p$ = 10J

Next is to calculate kinetic energy of the blocks :

$KE_{b} = \frac{1}{2} (m_1 + m_2).v^2\\KE_b= \frac{1}{2} (2+4).2^2$

$KE_b$ =12J

Therefore, the total kinetic energy will be

KE = $KE_p + KE_b$ =10 + 12

KE= 22J

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For each pair of vehicles, choose the vehicle that would experience the greatest force of impact in a collision. Type your answe

velikii [3]

Answer:

I need help on this tooo

Explanation:

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3 years ago