All categories

3 years ago

What's an electron transitions involves a photon emitting the least amount of energy?

Physics

1 answer:

FrozenT [24]3 years ago

4 0

Give me some answer choices and i will be happy to help

You might be interested in

How many grams of nitrogen gas are needed to produce 34 g of ammonia

scZoUnD [109]

Answer:

28 grams

Explanation:

The equation for the reaction is

3H(2) + N(2) -> 2NH(3)

Then we have.

The molar mass, M of ammonia is 17 g/mol.

34 grams of ammonia, NH3 then would be

34 g / 17 g/mol

= 2 moles

2 moles of ammonia will be obtained from

(2 * 1) / 2

= 1 mole of nitrogen

The molar masses of nitrogen is 28 g/mol

2 moles of nitrogen corresponds to 1 * 28 = 28 grams.

7 0

4 years ago

In amplitude modulation, which wave property remains constant?

NNADVOKAT [17]

The carrier frequency remains constant during amplitude modulation. :)

8 0

3 years ago

A wave with a speed of 437 m/s has a frequency of 28 hertz. What is the length of the wave?

Natasha2012 [34]

Answer: 15.6 metres

Explanation:

Given that:

length of wave (λ)= ?

Frequency of wave F = 28 Hertz

Speed of wave (V) = 437 m/s

The wavelength is the distance covered by the wave in one complete cycle. It is measured in metres, and represented by the symbol λ.

So, apply V = F λ

Make λ the subject formula

λ = V / F

λ = 437 m/s / 28 Hertz

λ = 15.6 m

Thus, the length of the wave is 15.6 metres

6 0

4 years ago

You push a 22.0 kg box along a rough floor at a constant velocity. The coefficient of kinetic friction between the box and the f

mars1129 [50]

The answer is actually 22.0

3 0

3 years ago

The mass of Tesla Model S is 2000 kg and its engine produces

yulyashka [42]

Answer:

The ratio of the power generated by the engines are $\dfrac{2}{3}$

(b) is correct option.

Explanation:

Given that,

Mass of Tesla = 2000 Kg

Torque = 400 Nm

Mass of Mercedes = 1.5 M Tesla

The Benz engine produces 50% more torque than the Tesla.

We need to calculate the power generated by the engines 6 seconds after a start from rest

Using formula of power

$P=F\cdot v$

We know that,

$v=at$

$v=\dfrac{F}{m}t$

$v=\dfrac{\tau}{mr}t$

Put the value of F and v in equation (I)

$P=\dfrac{\tau}{r}\times\dfrac{\tau}{mr}t$

$P=\dfrac{\tau^2t}{mr^2}$

Here, r and t are same for both bodies.

$P\propto\dfrac{\tau^2}{m}$

We need to calculate the ratio of the power generated by the engines

Using formula of power

$\dfrac{P_{T}}{P_{B}}=\dfrac{\tau_{T}^2}{m_{T}}\times\dfrac{m_{B}}{\tau_{B}}$

Put the value into the formula

$\dfrac{P_{T}}{P_{B}}=\dfrac{400^2}{2000}\times\dfrac{3000}{600^2}$

$\dfrac{P_{T}}{P_{B}}=\dfrac{2}{3}$

Hence, The ratio of the power generated by the engines are $\dfrac{2}{3}$

3 0

3 years ago