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loris [4]
3 years ago
11

Solve the equation using the quadratic formula.

Mathematics
2 answers:
vitfil [10]3 years ago
7 0

Answer:

x=\frac{-3\pm\sqrt{17}}{2}

Step-by-step explanation:

We have been given an equation x^2+3x-2=0. We are asked to solve the given equation.

To solve our given equation, we will use quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Substitute the values:

x=\frac{-3\pm\sqrt{3^2-4(1)(-2)}}{2(1)}

x=\frac{-3\pm\sqrt{9+8}}{2}

x=\frac{-3\pm\sqrt{17}}{2}

Therefore, option D is the correct choice.

gayaneshka [121]3 years ago
5 0
The last one is the answer

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Answer:

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Step-by-step explanation:

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Bottle A contains 4 ounces of water, which is 25% of the amount of water in Bottle B. How much water is there in Bottle B?
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Answer:

B=16 ounces

C=24 ounces

B=1/0.75=133%

Step-by-step explanation:

we have that

A≡0.25B (25%), if A=4 ounces  then B=4/0.25 = 16 ounces

C=1.5B (150%), if B=16 ounces then C=1.5*(16 ounces) = 24 ounces

D≡xB (?%), if D=12 ounces then x=12/16 = 0.75 ≡ 75%, but xB≡D ⇒ B≡D/x →

B≡12(1/0.75)= B=12*(1.333)→ B≅133%D

6 0
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Step-by-step explanation:

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<em>SIMPLY PLUGIN 4.8 FOR "A" EQUATION SHOULD LOOK LIKE V=4.8³ AND YOU WILL GET THE SAME ANSWER I DID</em>

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Read 2 more answers
Mr. Smith traveled to a city 300 miles from his home to attend a meeting. Due to car trouble, his average speed returning was 6
Kryger [21]

Answer: The speed at which he traveled to the city is 69.8 mph

Step-by-step explanation:

Let x represent the speed at which he traveled to the city.

Mr. Smith traveled to a city 300 miles from his home to attend a meeting.

Time = distance/speed

Time taken to travel to the city is

300/x

Due to car trouble, his average speed on returning was 6 mph less than his speed going. This means that the speed at which he returned is (x - 6) mph. Time taken to return from the city is

300/(x - 6)

If the total time for the round trip was 9 hours, it means that

300/x + 300/(x - 6) = 9

Cross multiplying by x(x - 6), it becomes

300(x - 6) + 300x = 9x(x - 6)

300x - 1800 + 300x = 9x² - 54x

9x² - 54x - 300x - 300x - 1800 = 0

9x² - 654x -1800 = 0

Applying the general quadratic equation,

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 9

b = - 654

c = 1800

Therefore,

x = [- - 654 ± √(- 654² - 4 × 9 × 1800)]/2 × 9

x = [654 ± √(427716 - 64800)]/18

x = [654 ± √362916.4]/18

x = (654 + 602.4)/2 or x = (654 - 602.4)/18

x = 1256.4/18 or x = 51.6/18

x = 69.8mph or x = 2.9 mph

The speed at which he traveled to the city is 69.8 mph

By checking,

Time spent travelling to the city = 300/69.8 = 4.3 hours

Time spent returning =

300/(69.8 - 6) = 4.7 hours

4.3 + 4.7 = 9 hours

3 0
3 years ago
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