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loris [4]
3 years ago
11

Solve the equation using the quadratic formula.

Mathematics
2 answers:
vitfil [10]3 years ago
7 0

Answer:

x=\frac{-3\pm\sqrt{17}}{2}

Step-by-step explanation:

We have been given an equation x^2+3x-2=0. We are asked to solve the given equation.

To solve our given equation, we will use quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Substitute the values:

x=\frac{-3\pm\sqrt{3^2-4(1)(-2)}}{2(1)}

x=\frac{-3\pm\sqrt{9+8}}{2}

x=\frac{-3\pm\sqrt{17}}{2}

Therefore, option D is the correct choice.

gayaneshka [121]3 years ago
5 0
The last one is the answer

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3 years ago
If 2a+b=6 and a−6=b, what is the value of a?
earnstyle [38]

Step-by-step explanation:

Given

2a + b = 6......equation 1

a - 6 = b

a = b + 6........equation 2

Putting equation 2 in equation 1

2 ( b + 6 ) + b = 6

2b + 12 + b = 6

3b = 6 - 12

3b = - 6

b = - 6 / 3

Therefore b = - 2

Now

a = - 2 + 6 = 4

hope it will help :)

3 0
3 years ago
Read 2 more answers
The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
FYI, I don't have many points.
zimovet [89]

Answer:

ok i see that question it would be 3

Step-by-step explanation:

6 0
3 years ago
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inn [45]

Answer:

147

Step-by-step explanation:

236-89=147

3 0
2 years ago
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