a. The speed of the pendulum when it reaches the bottom is 0.9 m/s.
b. The height reached by the pendulum is 0.038 m.
c. When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
<h3>Kinetic energy of the pendulum when it reaches bottom</h3>
K.E = 100%P.E - 18%P.E
where;
K.E(bottom) = 0.82P.E
K.E(bottom) = 0.82(mgh)
K.E(bottom) = 0.82(1 x 9.8 x 0.05) = 0.402 J
<h3>Speed of the pendulum</h3>
K.E = ¹/₂mv²
2K.E = mv²
v² = (2K.E)/m
v² = (2 x 0.402)/1
v² = 0.804
v = √0.804
v = 0.9 m/s
<h3>Final potential energy </h3>
P.E = 100%K.E - 7%K.E
P.E = 93%K.E
P.E = 0.93(0.402 J)
P.E = 0.374 J
<h3>Height reached by the pendulum</h3>
P.E = mgh
h = P.E/mg
h = (0.374)/(1 x 9.8)
h = 0.038 m
<h3>when the pendulum stops</h3>
When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
Thus, the speed of the pendulum when it reaches the bottom is 0.9 m/s.
The height reached by the pendulum is 0.038 m.
When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
Learn more about pendulum here: brainly.com/question/26449711
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Answer: The final mass of the tank is 2.46kg
Explanation: All shown in the attachment.
Assumptions:
i. Argon is treated as an ideal gas at the specified conditions.
ii. Isentropic relation of ideal gas applies at the given conditions.
Answer:
The vulture loses 6.1 m height
Explanation:
Please see the attached figure.
The horizontal distance and the loss of height form a 90º triangle.
The loss of height is the side opposite the given angle (3.5º) and the 100 m horizontal distance is adjacent the angle.
Then, using trigonometric rules:
(1) sin 3.5º = h / hyp
(2) cos 3.5º = distance / hyp
where
h = height lost during the flight.
hyp = hypotenuse of the triangle
Using (2) we can calculate the hypotenuse:
cos 3.5º = 100 m / hyp
hyp = 100 m / cos 3.5º = 100.2 m
with the hypotenuse we can now calculate the loss of height using (1):
sin 3.5º = h / hyp
sin 3.5º = h / 100.2 m
sin 3.5º * 100.2 m = h
<u>h = 6.1 m</u>
( very modest drop in height indeed!)
1). Contrary to what we think we see around us every day, NO force is required
to keep an object moving at a constant speed in a straight line.
Force is required to <u>change</u> the object's motion . . . speed it up, slow it down,
or change the direction in which it's moving.
2.a). The motion of the box changes from not moving to moving.
The forces on it are unbalanced.
2.b). The motion of the box doesn't change. It goes from not moving to
still not moving. The forces on it are balanced.
2.c). The motion of the box changes from moving to moving slower.
After you stop pushing, the forces on it are unbalanced.
Vacumn... but if it is a material i guess it is air.
