What is not an example of Absorption? (Physics)
1 answer:
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Answer:
Decreases
Explanation:
Gauss's law states that the flux of the electric field through a closed surface is equal to the quotient between the charge inside that surface divided by the permittivity of free space:
Therefore, the magnitude of the electric field is inversely proportional to the area, the area is directly proportional to the radius. So, as the radius of the Gaussian surface increases, the magnitude of the electric field at the surface decreases.
<h2>Question
</h2>
A particle, mass 0.25 kg is at a position (<em>-7i + 7j + 5k</em>) m, has a velocity (<em>6i - j + 4k</em>) m/s, and is subject to a force (<em>-5i + 0j - k</em>) N. What is the magnitude of the torque on the particle about the origin?
<h2>Answer:</h2>
47.94Nm
<h2>Explanation:</h2>The torque (τ) on a particle subject to a force (represented as force vector F) at a position (represented as position vector r) about the origin is given by the cross product of the position vector r for the point of application of a force and the force F. i.e
τ = r x F
Given:
r = (-7i + 7j + 5k) m
F = (-5i + 0j - k) N
| i j k |
r x F = | -7 7 5 |
| -5 0 -1 |
r x F = i(-7 - 0) - j(7+25) + k(0+35)
r x F = i(-7) - j(32) + k(35)
r x F = -7i - 32j + 35k
Therefore the torque τ = -7i - 32j + 35k
The magnitude of the torque is therefore;
|τ| =
|τ| =
|τ| =
|τ| = 47.94Nm
The magnitude of the torque on the particle about the origin is 47.94Nm