PE= 3kg x 10N/kg x 10m
= 300J
Answer
A. the work done on the refrigerant in each cycle is 105kJ
B the coefficient of performance of the refrigerator is 4.8
Explanation
Given data
Work done at high temperature T2 Qh=610kJ
Work done at low temperature T1 Ql=505kJ
We know that the net work done by the refrigerator is expressed as
Wnet= Qh-Ql
=610-505
=105kJ
Also we know that the coefficient of performance is expressed as
COP= Ql/Wnet
COP= 505/105
= 4.8
You know I’m going to be honest I don’t feel like it
Answer:
fact one
Explanation:
fact two is going slower and a longer distance than fact one so fact one will get there first.
hope this helps
There’s no picture and what’s the length?
