Answer:then he has a lot of gas
Explanation
I'm pretty sure the answer is B double check to make sure it isn't A
We are given the mass spectrum data for this compound which has a molecular ion peak of m+ = 91.043 m/z. When we have an m+ peak that is an odd number, that suggests that there are an odd number of nitrogens, in this case we'll assume 1 nitrogen atom to start. Nitrogen has a mass of 14 so we will substract that from our initial value.
91- 14 (1N) = 77 m/z
We are also told that there are carbon, hydrogens and oxygens present, so we will assume there is at least one oxygen which has a mass of 16 and subtract that value.
77 - 16 (1 O) = 61 m/z
Now we will try to get as close as possible to the remaining mass with carbons that has a mass of 12, and fill the remaining mass with hydrogens that have a mass of 1.
61 / 12 = 5
5 x 12 = 60
61 - 60 (5 C) = 1 m/z and this leaves us with 1 H.
The current formula would be C₅HON, but this structure is impossible since we do not have enough hydrogens to satisfy the carbons. So we can try to use 4 carbons instead and fill the rest with hydrogens.
4 x 12 = 48
61 - 48 (4 C) = 13 m/z and this leaves us with 13 H.
The current formula would be C₄H₁₃ON. The most hydrogens we can have in a compound is 2n+2 where n is the number of carbons. So with 4 carbons the most hydrogens we could have is 10. Therefore, our formula has too many hydrogens and also cannot work. So we cannot make up the remaining mass with carbons and hydrogens, therefore, we should add another oxygen before working with carbons and hydrogens.
61 - 16 (1 O) = 45 m/z
45/ 12 = 3.75
3 x 12 = 36
45 - 36 (3 C) = 9 m/z which gives us 9 hydrogens left.
The current formula is now C₃H₉O₂N. To test if this formula works we can calculate the double bond equivalents (DBE), also known as degrees of unsaturation.
DBE = C - H/2 + N/2 + 1 = 3 - (9/2) + (1/2) + 1 = 0
A value of 0 DBE tells us that there are no double bonds in this molecule but that the formula is a possibility so:
C₃H₉O₂N = 91 m/z
Answer:
Explanation:
To solve this problem, we have to remember the ideal gas theory. We going to use the Gay Lussac Law.
The equation is:
PiTo = PoTi
Where:
<em>Pi =initial pressure</em>
<em>Po = final pressure</em>
<em>Ti = initial temperature</em>
<em>To = final temperature</em>
Let's use this equation and replace the values:
<em>Pi = 107 kPa</em>
<em>Ti = 22°C</em>
<em>To = 45 °C </em>
<em>Po = ? </em>
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You can use the units as the problem gave you.
Using the Gay Lussac law:
107 kPa x 45 °C = Po x 22°C
Po = (4,815 kPa°C / 22°C) = 218.86 kPa
Po = 218 kPa
Answer:
(a) The slope of distance-time graph gives the speed of the objects.
As the slope of object (B) is the greatest among all, thus B has the largest speed and hence it is the fastest among all the objects.
(b) : As the curve of the objects do not intersect with each other even once, hence they cannot be at the same point on the road at the same time.
(c) : On the y axis (i.e. distance line), 7 small represents 4 km
∴ 1 small line =
7
4
=0.57 km
Position of C at the instant B passes A is 8 km
(d) ; Position of B at the instant it passes C is 2nd small line above 4 km i.e. 4+2×0.57=5.14 km
∴ Distance traveled by B =5.14−0=5.14 kmV
Explanation:
