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2 years ago

1) which power was given solely to the national goverment?

Physics

2 answers:

creativ13 [48]2 years ago

3 0

The answer is A the ability to coin money:)

Misha Larkins [42]2 years ago

3 0

A. ability to coin money :)

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A swift blow with the hand can break a pine board. As the hand hits the board, the kinetic energy of the hand is transformed int

Stells [14]

Answer:

A. The hand must move with a velocity of 6.98 m/s to break the board.

B. Average force on the hand = 1025 N

Explanation:

A.To determine the speed the hand must move with to break the board, the force workdone in breaking the board is found first.

Workdone = force × distance

Minimum force required = 870 N;

Distance moved by board/Deflection in order to break = 1.4 cm = 0.014 M

Workd done = 870 N × 0.014 m = 12.18 Nm or 12.18 J

This work done = Kinetic energy of the hand

Kinetic energy = mv²/2 ; where m is mass and v is velocity

Mass of hand = 0.50 Kg, velocity = ?, K.E. = 12.18 J

v² = 2 KE/m

v = √2KE/m

v = √(2 × 12.18/0.50)

v = 6.98 m/s

Therefore, the hand must move with a velocity of 6.98 m/s to break the board.

B. Average force on the hand

This can be determined using the equation of motion, v² = u² + 2as to find acceleration, since force = mass × acceleration

From the equation of motion, a = v² - u²/2s

At rest, v = 0, u = 6.98, s = 1.2 cm = 0.012 m

a = 0² - 6.98²/ 2 × 0.012

a = -2030 m/s²

Force = 2030 m/s² × 0. 50 kg = 1015 N

Therefore, Average force on the hand = 1025 N

3 0

2 years ago

What is the magnitude of an electric field that balances the weight of a plastic sphere of mass 2.1 g that has been charged to -

Liula [17]

Answer:

Electric field, $E=6.86\times 10^6\ N/C$

Explanation:

It is given that,

Mass of sphere, m = 2.1 g = 0.0021 kg

Charge, $q=-3\ nC=-3\times 10^{-9}\ C$

We need to find the magnitude of electric field that balances the weight of a plastic spheres. So,

$ma=qE$

a = g

$E=\dfrac{mg}{q}$

$E=\dfrac{0.0021\ kg\times 9.8\ m/s^2}{-3\times 10^{-9}\ C}$

$E=6860000\ N/C$

$E=6.86\times 10^6\ N/C$

Hence, the magnitude of electric field that balances its weight is $6.86\times 10^6\ N/C$ . Hence, this is the required solution.

4 0

3 years ago

Do you know any good books about physics and math?

horrorfan [7]

What Is Mathematics? Is a book about math

A book about physics /A Brief History of Time

5 0

2 years ago

How do I solve Q.14 & Q.15

timurjin [86]

14-needle heading west
15-the strength of the current and the distance

6 0

2 years ago

Find the electric potential VP at point P. [Hint: To input a natural logarithm into the answer box, simply type the letters "ln"

Alik [6]

Answer:

After finding the electric potential VP at point P = Q/Чπϵ₀L ㏑(1+ $\frac{L}{d}$ )

Explanation:

I believe it is a part C question.

The derivative of V and P will be directly proportional to the differential dq and the inverse of Чπϵ₀δ........

Please find detailed solution in the attached picture as i believe that is the answer to the part C question you are seeking for.

8 0

3 years ago