The probability that Rebecka selects a terrier and Aaron selects a retriever is 10/121
<h3>How to determine the probability?</h3>
The distribution of the puppies is given as:
4 poodles, 5 terriers, and 2 retrievers
The probability of selecting a terrier is;
P(terrier) = 5/11
The probability of selecting a retriever is;
P(retriever) = 2/11
The required probability is
P = 5/11 * 2/11
Evaluate
P = 10/121
Hence, the probability that Rebecka selects a terrier and Aaron selects a retriever is 10/121
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X + 2x + x + 10 = 90
4x = 80
x = 20
Hi! For this question all you have to do is subtract 43 from 72.
72 - 43 = 29
Trina had 29 stamps left.
Hope this helps! Happy Thanksgiving!
Answer:
none of the above
Step-by-step explanation:
The problem as written cannot have any of the solutions offered.
For any of those choices, the right side expression will be irrational. The left side expression will be rational for any rational value of x, so cannot be equal to the right-side expression.
The solution is an irrational number near ...
x ≈ 1.33682898582
We know, Volume of a Sphere = 4/3 πr³
v = 4/3 * 3.14 * 18³
v = 4.186 * 5832
v = 24,416.64 cm³
Volume of a Sphere = 4/3 πr³
v = 4/3 * 3.14 * 12³
v = 4.186 * 1728
v = 7234.56 cm³
Difference = 24,416.64 - 7234.56 = 17182.08
In short, Your Answer would be: 17182.08 cm³
Hope this helps!
