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Nadusha1986 [10]
3 years ago
5

Two trains left Mooseport at the same time. One traveled north at 83 mph. The other traveled south at 67 mph. After how many hou

rs were the two trains 600 miles apart?
If you can show work, that would be great!
Mathematics
2 answers:
oee [108]3 years ago
8 0

First of all, remember if 2 people are walking away from each other at the same speed (ex 4 mph), after 1 mile, they would be 8 miles away. 4 miles south and north. So these trains go away from each other at a total of 150 mph( 67 + 83). So your equation is h = hours, 150h = 600. Divide both sides by 150 to get h = 4. 4 hours is your answer.

algol133 years ago
7 0
I think the answer is 4 hours apart


X * ( 67+83)=600

X * (150)=600

600/150= 4

4 Is the answer
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a gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sel
adell [148]

Answer:

The price per wind chime that will maximize revenue = $ 315

Step-by-step explanation:

Given - A gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sell 5 fewer wind chimes per month.

To find - Find the price per wind chime that will maximize revenue.

Proof -

Given that,

Total Wind chimes selling = 160

Price of each Wind chime = $150

Now,

Given that, for each $15 increase in price, they will sell 5 fewer wind chimes per month.

So,

Let the price = 150 + 15x

So,

Number of wind Chimes sold per month = 160 - 5x

So,

Total Revenue, R = (150 + 15x)(160 - 5x)

                             = 24000 - 750x + 2400x - 75x²

                             = 24000 + 1650x - 75x²

⇒R(x) = 24000 + 1650x - 75x²

Differentiate R with respect to x , we get

R'(x) = 1650 - 150x

Now,

For Maximize Revenue, Put R'(x) = 0

⇒1650 - 150x = 0

⇒150x = 1650

⇒x = 1650/150

⇒x = 11

∴ we get

Price per Wind chime = $ 150 + 15(11)

                                    = $ 150 + 165

                                    = $ 315

So,

The price per wind chime that will maximize revenue = $ 315

3 0
3 years ago
Find the median mode range and any outliers. Then describe the data using them 77777,88,555,6,99,10101010,12
umka2103 [35]

Answer:

The median = 5

The mode  = 7

Range = 5

Outliers= None

Step-by-step explanation:

The median is the  value of the middle term.

The median is that value which divides the data into two equal halves.

7,7,7,7,7,8,8,5,5,5,6,9,9,10,10,10,10,12

There are 18 terms . So the middle term would be 9th term value= 5

The mode is the value which is repeated the most. = 7

Range is the difference between the highest and lowest value.= 12- 7= 5

The interquartile range, IQR= q3 - q1 where q3= 10 and q1= 7

IQR= 10 −7=3

The inner fences can be found out by

q1−(1.5*IQR) and q3+(1.5*IQR)

=7−(1.5*3) and 10+(1.5*3)

Inner fences: 2.5 and 14.5

The outer fences are q1−(3*IQR) and q3+(3*IQR)

=7−(3*3) and 10+(3*3)

Outer fences: -2 and 19

So if there are any outliers in this data set, they will either be less than -2 or greater than 19. But there are no outliers.

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the angle would be 180

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