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Westkost [7]
3 years ago
15

Which expression is equivalent to 2^2×2/2^4

Mathematics
1 answer:
dusya [7]3 years ago
6 0
First step is to simplify the equation so that it makes our life easier! Since 2^2 is equivalent to 4, we can plug that into the equation. Then we can also simplify 2^4 to 16. Now it should look like this:

(4)(2)/16

Now we can solve. 4(2) = 8 so now we have 8/16. 8/16 simplifies to 1/8 when you divide the numerator and the denominator by 8. So there you go! Your final answer is 1/8! I really hope that helped you out, and happy holidays!
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I need to understand the solution
alina1380 [7]

Answer:

17:3

Step-by-step explanation:

Hope this helps!

5 0
2 years ago
Jamie had 4/5 of a spool of twine. He then used 1/2 of a spool of twine to make friendship knots. Over. Explain how you know whe
Ganezh [65]

Answer:

Jamie's claims are correct because 3/10 of the spool twine is left over after using 1/2 of the spool twin for friendship knot

Step-by-step explanation:

Full question: He claims to have 3/10 of the original spool of twine leftover.

First, we compare 3/10 with 4/5 - 1/2

The lowest common multiple for2 and 5 is 10.

To write 4/5 as a fraction with common denominator, multiply numerator and denominator by 2

4/5 = (4×2)/(5×2) = 8/10

To write 1/2 as a fraction with a common denominator, multiply denominator and numerator by5

1/2 =(1×5)/(2×5) = 5/0

So we have :

8/10 - 5/10

Since denominators are equal ,we go ahead and subtract

8/10 - 5/10 = (8-5)/10 = 3/10

4 0
3 years ago
In a recent​ year, an author wrote 171 checks. Use the Poisson distribution to find the probability​ that, on a randomly selecte
sveticcg [70]

Answer: 0.3741

Step-by-step explanation:

Poison probability ;

P(x) = [U(^x) e(^-U)] ÷ x!

Where U = mean

Note: e = exponential symbol

Number of checks that year = 171

Number of days in a year = 365

U = 171/365 = 0.468

Average checks per day = 0.4685

Probability that at least one check was written per day is can be calculated by;

P(not 0) = 1 - P(0)

Therefore,

P(x) = [U(^x) e(^-U)] ÷ x!

P(0) = [ 0.4685^0 * e^-0.4685] ÷ 0!

P(0) = [ 1 * 0.6259] ÷ 1

P(0) = 0.6259

Therefore,

P(not 0) = 1 - 0.6259 = 0.3741

4 0
2 years ago
A student solves the following equation for all possible values of x:
bekas [8.4K]
<span><u><em>The correct answer is: </em></u>
C) his solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

<u><em>Explanation: </em></u>
<span><u>To solve this rational equation, we cross multiply: </u>
8*(x-4)=2*(x+2).

<u>Using the distributive property, we have </u>
8*x-8*4=2*x+2*2;
8x-32=2x+4.

<u>Subtract 2x from each side: </u>
8x-32-2x=2x+4-2x;
6x-32=4.

<u>Add 32 to each side: </u>
6x-32+32=4+32;
6x=36.

<u>Divide both sides by 6:</u>
</span></span>\frac{6x}{6}<span><span>=</span></span>\frac{36}{6}<span><span>;
x=6.

<u>Extraneous solutions</u> are solutions that come about in the problem but are not valid solutions to the problem; the only values of x that would give this sort of answer are -2 and 4, since these are the two values that would make one of the denominators 0 (we cannot divide by 0).</span></span>
6 0
2 years ago
Read 2 more answers
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