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3 years ago

Moira is drawing the electric field lines around a pair of charges. One charge is positive, and the other charge is negative.

1 answer:

8 0

The best answer is B. If you curve them away, they have a less tendency to be attracted to the pair of charges and would stay around the pair instead of interacting with them.

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This term means pertaining to or exist at or from the very beginning.

dalvyx [7]

A. Primordial means to exists from the very beginning.

5 0

3 years ago

Assume that a machine puts out 8000 joules of work when the user puts in 10,000 joules of work. What is the efficiency of the ma

-BARSIC- [3]

Answer:

80 Percent

Explanation:

E=energy output/energy input×100

E=8000/10000×100

E=0.8×100

E=80 percent.

Mark brianliest if my answer suit your question

6 0

3 years ago

A plant was placed in the corner of a room away from a window. What might you observe about the plant after five days?

Readme [11.4K]

Answer:

4 the plant is leaning towards the window

Explanation:

that is due to the plant inhabit to grow towards the sunlight so the plants tries its best to get the sunlight by doing so and growing

4 0

3 years ago

A 730-keV gamma ray Compton-scatters from an electron. Find the energy of the photon scattered at 120°, the kinetic energy of th

romanna [79]

Answer:

Energy of scattered photon is 232.27 keV.

Kinetic energy of recoil electron is 497.73 keV.

The recoil angle of electron is 13.40°

Explanation:

The energy of scattered photon is given by the relation :

$E_{2}=\frac{E_{1} }{1+(\frac{E_{1} }{m_{e}c^{2} })(1-\cos\theta) }$ .....(1)

Here E₁ is the energy of incident photon, E₂ is the energy of scattered photon, $m_{e}$ is mass of electron and θ is scattered angle.

Substitute 730 keV for E₁, 511 keV for $m_{e}$ and 120° for θ in equation (1).

$E_{2}=\frac{730 }{1+(\frac{730 }{511 })(1-\cos120) }$

E₂ = 232.27 keV

Kinetic energy of recoil electron is given by the relation :

K.E. = E₁ - E₂ = (730 - 232.27 ) keV = 497.73 keV

The recoil angle of electron is given by :

$\cot\phi=(1+\frac{E_{1} }{m_{e}c^{2} })\tan\frac{\theta}{2}$

Substitute the suitable values in above equation.

$\cot\phi=(1+\frac{730 }{511 })\tan\frac{120}{2}$

$\cot\phi=4.20$

$\phi$ = 13.40°

8 0

3 years ago

Man start to moves from point A (Initial Point) to Point B (Final Point) in a given

mash [69]

Answer:

Image not full.

Explanation:

From what I can see, Displacement is 175m,

Distance will be = 100 + 50 + the hidden value on the bottom right

4 0

3 years ago