Answer:
A. The sum of all the forces acting on an object.
Answer:
mass=367kg
force=183N
acceleration =?
Now,
force=m×a
183=367×a
183÷367=a
0.49=a
acceleration =0.49m/s^2 answer!!!!
Answer:
![\lambda= 506.25 nm](https://tex.z-dn.net/?f=%5Clambda%3D%20506.25%20nm)
Explanation:
Diffraction is observed when a wave is distorted by an obstacle whose dimensions are comparable to the wavelength. The simplest case corresponds to the Fraunhofer diffraction, in which the obstacle is a long, narrow slit, so we can ignore the effects of extremes.
This is a simple case, in which we can use the Fraunhofer single slit diffraction equation:
![y=\frac{m \lambda D}{a}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bm%20%5Clambda%20D%7D%7Ba%7D)
Where:
![y=Displacement\hspace{3}from\hspace{3} the\hspace{3} centerline \hspace{3}for \hspace{3}minimum\hspace{3} intensity =1.35mm\\\lambda=Light\hspace{3} wavelength \\D=Distance\hspace{3}between\hspace{3}the\hspace{3}screen\hspace{3}and\hspace{3}the\hspace{3}slit=2m\\a=width\hspace{3}of\hspace{3}the\hspace{3}slit=0.750mm\\m=Order\hspace{3}number=1](https://tex.z-dn.net/?f=y%3DDisplacement%5Chspace%7B3%7Dfrom%5Chspace%7B3%7D%20the%5Chspace%7B3%7D%20centerline%20%5Chspace%7B3%7Dfor%20%5Chspace%7B3%7Dminimum%5Chspace%7B3%7D%20intensity%20%3D1.35mm%5C%5C%5Clambda%3DLight%5Chspace%7B3%7D%20wavelength%20%5C%5CD%3DDistance%5Chspace%7B3%7Dbetween%5Chspace%7B3%7Dthe%5Chspace%7B3%7Dscreen%5Chspace%7B3%7Dand%5Chspace%7B3%7Dthe%5Chspace%7B3%7Dslit%3D2m%5C%5Ca%3Dwidth%5Chspace%7B3%7Dof%5Chspace%7B3%7Dthe%5Chspace%7B3%7Dslit%3D0.750mm%5C%5Cm%3DOrder%5Chspace%7B3%7Dnumber%3D1)
Solving for λ:
![\lambda=\frac{y*a}{mD}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7By%2Aa%7D%7BmD%7D)
Replacing the data provided by the problem:
![\lambda=\frac{(1.35\times 10^{-3})*(0.750\times 10^{-3})}{1*2} =5.0625\times 10^{-7}m =506.25nm](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B%281.35%5Ctimes%2010%5E%7B-3%7D%29%2A%280.750%5Ctimes%2010%5E%7B-3%7D%29%7D%7B1%2A2%7D%20%3D5.0625%5Ctimes%2010%5E%7B-7%7Dm%20%3D506.25nm)
Answer: well first you have to show or tell us the “error“ Selena made
Explanation:
Kinetic energy= 1/2 m v^2
so... 1/2(1350)(12^2)
kinetic energy = 97200Joules