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natulia [17]
3 years ago
8

A star is born when gas and dust from a nebula become so dense and hot that nuclear fusion starts. Which of the following forces

is responsible for the formation of a star?
A.
friction
B.
gravitation
C.
magnetism
D.
electromagnetic energy
Physics
2 answers:
Kitty [74]3 years ago
8 0
Your Question:
<span>A star is born when gas and dust from a nebula become so dense and hot that nuclear fusion starts. Which of the following forces is responsible for the formation of a star?
A.
friction
B.
gravitation
C.
magnetism
D.
electromagnetic energy</span>
Our Teams Answer: B. Gravitation

Our Teams aim's to please and We are happy to help! Its the answer is wrong please notify us quickly for we can fix it quickly! Thanks :)

-ExperimentsDIY

LenaWriter [7]3 years ago
4 0

Answer: B.  gravitation

Explanation:

Nebula is a stellar nursery. It is composed of dust and gases. This molecular cloud condenses under its own weight and forms a core which spins and gathers more mass due to gravity. This causes temperature and pressure to rise which kicks in the nuclear fusion reaction and a star is said to be born.

Thus, gravitation is responsible for formation of star.

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Which of the following factors most affect the rate at which waves erode land features along the shore?
OLEGan [10]

Answer:

The biggest factor affecting coastal erosion is the strength of the waves breaking along the coastline. A wave's strength is controlled by its fetch and the wind speed. Longer fetches & stronger winds create bigger, more powerful waves that have more erosive power.

Explanation:

hope it helps !

5 0
2 years ago
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Solve:40KMEN
Oksanka [162]

The spider will cross the driveway <u>25.71 in seconds</u>.

Why?

It's a conversion problem, so, in order to solve it, we need to convert the units of the given information.

Let's convert the given speed (in cm/s) to m/s.

We know that:

1m=100cm

So, converting we have:

14\frac{cm}{s}*\frac{1m}{100cm}=0.14\frac{m}{s}

Then, calculating the time, we have:

distance=speed*time\\\\3.6m=0.14\frac{m}{s}*time\\\\time=\frac{3.6m}{0.14\frac{m}{s}}=25.71s

We have that the spider will cross the driveway in 25.71 seconds.

Have a nice day!

8 0
3 years ago
A truck pushes a mound of dirt 5 meters with a force of 75 newtons. How much work has been done ?
Paladinen [302]

Work = force × distance, assuming that the force is parallel to displacement.

Work L=75×5=375J

6 0
3 years ago
A curve that has a radius of 90 m is banked at an angle of =10.8∘. If a 1100 kg car navigates the curve at 75 km/h without skidd
PilotLPTM [1.2K]

The minimum coefficient of static friction  between the pavement and the tires is 0.69.

The given parameters;

  • <em>radius of the curve, r = 90 m</em>
  • <em>angle of inclination, θ = 10.8⁰</em>
  • <em>speed of the car, v = 75 km/h = 20.83 m/s</em>
  • <em>mass of the car, m = 1100 kg</em>

The normal force on the car is calculated as follows;

F_n = mgcos(\theta)

The frictional force between the car and the road is calculated as;

F_k = \mu_k F_n\\\\F_k = \mu_k mgcos(\theta)

The net force on the car is calculated as follows;

mgsin(\theta) +  \mu_s mgcos(\theta) = \frac{mv^2}{r} \\\\mg(sin\theta \ + \ \mu_s cos\theta)= \frac{mv^2}{r} \\\\g(sin\theta \ + \ \mu_s cos\theta)= \frac{v^2}{r}\\\\sin\theta \ + \ \mu_s cos\theta = \frac{v^2}{rg}\\\\\mu_s cos\theta = sin\theta \  + \ \frac{v^2}{rg}\\\\\mu_s = \frac{sin\theta}{cos \theta} + \frac{v^2}{cos (\theta)rg}\\\\\mu_s = tan(\theta) +   \frac{v^2}{cos (\theta)rg}\\\\\mu_s = tan(10.8) +  \frac{(20.83)^2}{cos(10.8) \times 90 \times 9.8} \\\\\mu_s = 0.19 + 0.5\\\\

\mu_s = 0.69

Thus, the minimum coefficient of static friction  between the pavement and the tires is 0.69.

Learn more here:brainly.com/question/15415163

8 0
3 years ago
What equation explains the relation between amperes, watts and volts?
I am Lyosha [343]
I think Option B, i’m sorry if that’s wrong.
7 0
3 years ago
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