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natulia [17]
2 years ago
8

A star is born when gas and dust from a nebula become so dense and hot that nuclear fusion starts. Which of the following forces

is responsible for the formation of a star?
A.
friction
B.
gravitation
C.
magnetism
D.
electromagnetic energy
Physics
2 answers:
Kitty [74]2 years ago
8 0
Your Question:
<span>A star is born when gas and dust from a nebula become so dense and hot that nuclear fusion starts. Which of the following forces is responsible for the formation of a star?
A.
friction
B.
gravitation
C.
magnetism
D.
electromagnetic energy</span>
Our Teams Answer: B. Gravitation

Our Teams aim's to please and We are happy to help! Its the answer is wrong please notify us quickly for we can fix it quickly! Thanks :)

-ExperimentsDIY

LenaWriter [7]2 years ago
4 0

Answer: B.  gravitation

Explanation:

Nebula is a stellar nursery. It is composed of dust and gases. This molecular cloud condenses under its own weight and forms a core which spins and gathers more mass due to gravity. This causes temperature and pressure to rise which kicks in the nuclear fusion reaction and a star is said to be born.

Thus, gravitation is responsible for formation of star.

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Objects 1 and 2 attract each other with a electrostatic force of 18.0 units. If the charge of Object 2 is tripled, then the new
Leya [2.2K]

Answer:

The force will be 54.0 units

Explanation:

The magnitude of the electrostatic force between two charged objects is given by Coulomb's Law:

F=\frac{kq_1 q_2}{r^2}

where

k is Coulomb's constant

q1, q2 are the magnitude of the two charges

r is the separation between the two charges

From the equation, we see that the magnitude of the force is directly proportional to the charge of object 2:

F\propto q_2

In this problem, the initial force between the two objects is

F = 18.0 N

And so, when the charge on object 2 is tripled,

q_2'=3q_2

The new electrostatic force will be

F'\propto q_2' = (3q_2) = 3F

So, the force will also triple: since the original force was 18.0 units, the new force will be

F'=3F=3(18.0)=54.0

5 0
3 years ago
An alpha particle travels at a velocity of magnitude 550 m/s through a uniform magnetic field of magnitude 0.045T. (An alpha par
creativ13 [48]

Answer:

the force is perpendicular to the speed, it is a type of force that changes the direction of the speed, as in the uniform circular motion te, but does not change its modulus.

Explanation:

The magnetic force is given by the expression

    F = q v x B

The bold are vectors, where v is the velocity and B is the magnetic field, the product is the cross product whose result is a vector perpendicular to the two vectors (v and B)

From the above, the force is perpendicular to the speed, it is a type of force that changes the direction of the speed, as in the uniform circular motion te, but does not change its modulus.

   

Even when the change in direction is real and is caused by a centripetal force

For there to be a change in the velocity modulus there must be a force parallel to the velocity direction, generally a force in electrical

3 0
3 years ago
What is one way that light waves differ from sound waves?(1 point)
Shalnov [3]
Light waves are transverse while sound waves are longitudinal. Light waves can travel in vacuum. Sound waves require a material medium to travel, and hence, cannot travel in vacuum. The speed of light in a medium is constant.

Hope this helps!
Please give Brainliest!
7 0
1 year ago
a 60 kg woman in a elevator is accelerating upward at a rate of 1.2 m/s2. What is the gravitational force acting upon the woman?
Flura [38]

The gravitational force acting upon the woman is equal to <u>-588.6N</u>

Why?

To solve the problem, we need to consider that two forces are acting upon the woman, the first one is related to her weight and the second one is related to the acceleration of the elevator.

Gravitational force acting upon the woman:

Force=m*gravityacceleration\\\\Force=60kg*-9.81\frac{m}{s^{2}}=-588.6N

Hence, we have that the gravitational force acting upon the woman is equal to -588.6N.

Have a nice day!

5 0
2 years ago
Estimate the average force that a baseball pitcher's hand exerts on a 0.145-kg baseball as he throws a 40-m/s pitch. Assume the
Kitty [74]

Answer:

38.67 N

Explanation:

v = Final velocity = 40 m/s

u = Initial velocity

m = Mass of ball = 0.145kg

s = Displacement of ball = 3 m

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{40^2-0^2}{2\times 3}=\frac{800}{3}\ m/s^2

F=ma

\\\Rightarrow F=0.145\times \frac{800}{3}\\\Rightarrow F=38.67\ N

∴ Average force that a baseball pitcher's hand exerts on the ball is 38.67 N

6 0
3 years ago
Read 2 more answers
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