an 269 kg object is moved a distance of 1.9 m by a force if 580 j of work is done on the object what is the object acceleration
1 answer:
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Answer:
option C
Explanation:
given,
diameter of circular room = 8 m
rotational velocity of the rider = 45 rev/min
=
=4.712 rad/s
here in this case normal force is equal to centripetal force
N = m r ω²
N = m x 4 x 4.712²
N = 88.83m
frictional force = μ N
= 88.83m x μ
now, for the body to not to slide
gravity force is equal to frictional force
m g = 88.83 m x μ
g = 88.83 x μ
9.8 = 88.83 x μ
μ = 0.11
hence, the correct answer is option C
Answer:
The lifetime of the particle is
Explanation:
From the question we are told that
The average rest energy is
The intrinsic width is
The lifetime is mathematically represented as
Where h is the Planck's constant with a value of
substituting values