The formula we can use in
this case would be:
v = sqrt (T / (m / l))
Where,
v = is the velocity of the
transverse wave = unknown (?)
T = is the tension on the
rope = 500 N
m = is the mass of the
rope = 60.0 g = 0.06 kg
l = is the
length of the rope = 2.00 m
Substituting the given values into the equation to search
for the speed v:
v = sqrt (500 N/(0.06 kg /2 m))
v = sqrt (500 * 2 / 0.06)
v = sqrt (16,666.67)
<span>v = 129.10 m/s</span>
Positive will react better together. But opposites will try to get as far away as possible.
Answer:
Wm = 97.2 [N]
Explanation:
We must make it clear that mass and weight are two different terms, the mass is always preserved that is to say this will never vary regardless of the location of the object. While weight is defined as the product of mass by gravitational acceleration.
W = m*g
where:
m = mass = 60 [kg]
g = gravity acceleration = 10 [m/s²]
But in order to calculate the weight of the body on the moon, we must know the gravitational acceleration of the moon. Performing a search of this value on the internet, we find that the moon's gravity is.
gm = 1.62 [m/s²]
Wm = 60*1.62
Wm = 97.2 [N]
Answer:
they can blend in with their suroundings
Explanation:
Answer:
g=9.64m/s^2.
Explanation:
Gravitational field strength (in other words, gravitational acceleration) is given as follows:g=GMR2g=R2GMwhere G=6.674×10−11m3kg⋅s2G=6.674×10−11kg⋅s2m3 is the gravitational constant, M=5.972×1024kgM=5.972×1024kg is the mass of the Earth, and R=6.371×106m+0.06×106m=6.431×106mR=6.371×106m+0.06×106m=6.431×106m is the distance from the center of the Earth to the required point above the surface (radius plus 60 km).
