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BlackZzzverrR [31]
4 years ago
13

14. A rocket is shot up into the air and then comes back down and hits the ground 9.2 second later.

Physics
1 answer:
sineoko [7]4 years ago
3 0

Answer:

105.8 m

46 m/s

Explanation:

From the time the rocket is launched to the time it reaches its maximum height:

v = 0 m/s

a = -10 m/s²

t = 9.2 s / 2 = 4.6 s

Find: Δy and v₀

Δy = vt − ½ at²

Δy = (0 m/s) (4.6 s) − ½ (-10 m/s²) (4.6 s)²

Δy = 105.8 m

v = at + v₀

0 m/s = (-10 m/s²) (4.6 s) + v₀

v₀ = 46 m/s

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Two loudspeakers, A and B are driven by the same amplifier
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<h3><u>Complete Question </u></h3>

Q)Two loudspeakers, A and B, are driven by the same amplifier as shown and emit sinusoidal waves in phase. Speaker B is 2.00 m to the right of speaker A. Consider point Q along the extension of the line connecting the speakers, 1.00 m to the right of speaker B. Both speakers emit sound waves that travel directly from the speaker to point Q. a) What is the lowest frequency for which constructive interference occurs at point Q? b) What is the lowest frequency for which destructive interference occurs at point Q? The speed of sound wave is 344 m/s.

Answer:

lowest frequency is 172 Hz. for n = 1

lowest frequency is 86 Hz for n = 0

Explanation:

(a) Constructive interference takes place when the path difference is n where n=1,2,3 ...

frequency f = v /λn

                      = v n / d  

                       = n ( 344 / 2 )

                       = n ( 172 ) Hz.

lowest frequency is 172 Hz

b)Destructive interference takes place when the path difference is n/2 x  where n=1,3,5 ...

λ = 4/2n+1

for n = 0

λ = 4m

f = 344/4

f = 86 Hz.

lowest frequency is 86 Hz

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Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the vol
Alex_Xolod [135]

Answer:

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now we know that

v_1 = 2v_2

v_1 = \frac{1}{3}v_3

now plug in all the values in it

54 = v_1 + \frac{v_1}{2} + 3v_1

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The initial concentration of N2O4 is 0.45M The system is heated and allowed to reach equilibrium. At equilibrium concentration o
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K_c=\frac{(0.6)^2}{(0.15)}

K_c=2.4

Therefore, the value of equilibrium constant K_c for the following reaction will be, 2.4

3 0
3 years ago
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