1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bas_tet [7]
3 years ago
12

At what height does a 1000-kg mass have a potential energy of 1J relative to the ground? Be sure to show all work to support you

r answer.
Physics
1 answer:
nikdorinn [45]3 years ago
7 0
Potential energy = (mass) x (gravity) x (height)

       1 joule  =  (1,000 kg) x (9.8 m/s²) x (height)

       Height =  1 joule / (9,800 newtons)

                   =  1/9800 meter

                   =  0.000102 meter

                   =   0.102 millimeter    (rounded) 
You might be interested in
Pls help I need this done soon 50 points
lidiya [134]

Answer:

1,3,5

Explanation:

i think maybe dont come at me

6 0
3 years ago
Read 2 more answers
Calculate the orbital speed (in m/s) of a satellite that circles the Earth with a time period of 12.00 hours. The mass of the Ea
Hoochie [10]

Answer:

v = 3869 m/s

Explanation:

As we know that the orbital speed of the satellite is given as

v = \sqrt{\frac{GM}{r}}

also we know that

time period of the revolution is given as

T = \frac{2\pi r}{v}

now from above equation we know that

T = \frac{2\pi (\frac{GM}{v^2})}{v}

T = \frac{2\pi GM}{v^3}

so we will have

v = (\frac{2\pi GM}{T})^{1/3}

now plug in all data in this equation

v = (\frac{2\pi (6.67 \times 10^{-11})(5.97 \times 10^{24})}{12 \times 3600})^{1/3}

v = 3869 m/s

3 0
2 years ago
Two identical bodies are sliding toward each other on a frictionless surface. One moves at 1 m/s and the other at 2 m/s. They co
mario62 [17]

Answer:

V=\dfrac{3}{2}\ m/s

Explanation:

Two identical bodies are sliding toward each other on a frictionless surface.

Initial speed of body 1, m₁ = 1 m/s

Initial speed of body 2, m₂ = 2 m/s

They collide and stick.

We need to find the speed of the combined mass. Let V is the speed of the combined mass.

Using the conservation of momentum.

m_1u_1+m_2u_2=V(m_1+m_2)

We have, m₁ = m₂ = m

m\times 1+m\times 2=(m+m)V\\\\m+2m=2m\times V\\\\3m=2mV\\\\V=\dfrac{3}{2}\ m/s

So, the speed of the combined mass is \dfrac{3}{2}\ m/s.

6 0
2 years ago
what is a hypothesis reffered to as after being verified by a large number or independent experiments
Iteru [2.4K]

Answer:

The hypothesis may or may not be true and needs to be tested. It might be the answer to the problem. Hence, it must be tested thoroughly. When these predictions are tested again and again in independent scientific experiments and gets verified, the hypothesis is converted into a scientific theory.

7 0
3 years ago
HELP
astraxan [27]

Answer:

Ultraviolet light has shorter wavelengths than infrared light. The frequency of ultraviolet light is greater than that of infrared light. Ultraviolet light is higher in energy than infrared light.

7 0
3 years ago
Other questions:
  • What is the primary body that influences Earth's ocean tides? A. the Moon B. Venus C. Mars D. the Sun
    5·2 answers
  • What height (displacement) will a ball reach if thrown upward with an initial velocity of 15 m/s
    11·1 answer
  • Derive a relation between time period anf frequency of a wave
    7·1 answer
  • 0.235 moles of a diatomic gas expands doing 205 J of work while the temperature drops 88 K. Find Q.? (Unit=J)
    7·1 answer
  • Is a lung a living organism, why or why not?
    12·1 answer
  • What type of energy requires the motion of an object?
    6·1 answer
  • Can someone help me?
    15·1 answer
  • At an ocean depth of 10.0m, a diver's lung capacity is 2.40L. The air temperature is 32.0°C and the pressure is 101.30 kPa. What
    5·1 answer
  • Speed and time play a major factor in:
    13·2 answers
  • What is your initial speed if you accelerate at 5.8 m/s/s for 3.0 seconds and achieve a final speed of 45 m/s?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!