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Bas_tet [7]
3 years ago
12

At what height does a 1000-kg mass have a potential energy of 1J relative to the ground? Be sure to show all work to support you

r answer.
Physics
1 answer:
nikdorinn [45]3 years ago
7 0
Potential energy = (mass) x (gravity) x (height)

       1 joule  =  (1,000 kg) x (9.8 m/s²) x (height)

       Height =  1 joule / (9,800 newtons)

                   =  1/9800 meter

                   =  0.000102 meter

                   =   0.102 millimeter    (rounded) 
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proof in explanation

Explanation:

First, we will calculate the number of half-lives:

n = \frac{t}{t_{1/2}}

where,

n = no. of half-lives = ?

t = total time passed = 2100 million years

t_{1/2} = half-life = 700 million years

Therefore,

n = \frac{2100\ million\ years}{700\ million\ years}\\\\n = 3

Now, we will calculate the number of uranium nuclei left (n_u):

n_u = \frac{1}{2^{n} }(total\ nuclei)\\\\n_u = \frac{1}{2^{3} }(6400\ million)\\\\n_u = \frac{1}{8}(6400\ million)\\\\n_u =  800\ million

and the rest of the uranium nuclei will become thorium nuclei (u_{th})

n_{th} = total\ nuclei - n_u\\n_{th} = 6400\ million-800\ million\\n_{th} = 5600\ million

dividing both:

\frac{n_{th}}{n_u}=\frac{5600\ million}{800\ million} \\\\n_{th} = 7n_u

<u>Hence, it is proven that after 2100 million years there are seven times more thorium nuclei than uranium nuclei in the rock.</u>

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lcompute the increase in length of 500 m of copper wire when it's temperature changes from 12 degrees celsius to 32 degrees Cels
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Explanation:

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