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3 years ago

In your opinion, is "avoiding" an effective conflict management strategy? Why or why not?

2 answers:

6 0

I don't think avoiding would be an effective conflict management strategy, because if it's something serious or even something small you shouldn't really ever avoid anything especially if it's between you and another person because it could damage something between you two for awhile or maybe forever. So no i don't think that is a good why to handle something.

soldi70 [24.7K]3 years ago

4 0

In my personal opinion, avoiding in not an effective conflict management strategy. When you are avoiding a conflict, you are really just pushing it to the side and it will need to be dealt with sooner or later. Avoiding a conflict is also ammeter thing to do as well, you should take responsibility and handle any situation.

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Hi!!!! I WILL MARK YOU BRAINLIEST! PLEASE LEAVE AN ANSWER SOON!!!!

Crazy boy [7]

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Explanation:

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2 years ago

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fredd [130]

I think its snow. Yup.

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2 years ago

Read 2 more answers

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed?(a) 16(b

maw [93]

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed: 2.

<h3>What is kinetic energy?</h3>

A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.
Kinetic energy comes in five forms: radiant, thermal, acoustic, electrical, and mechanical.
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Explain that a moving object's mass and speed are two factors that impact the amount of kinetic energy it will possess.

The kinetic energy of an object is increased by a factor of 4 . By what factor is the magnitude of its momentum changed: 2.

To learn more about kinetic energy, refer to:

brainly.com/question/25959744

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4 0

1 year ago

Calculate the orbital period of a dwarf planet found to have a semimajor axis of a = 4.0x 10^12 meters in seconds and years.

padilas [110]

Explanation:

We have,

Semimajor axis is $4\times 10^{12}\ m$

It is required to find the orbital period of a dwarf planet. Let T is time period. The relation between the time period and the semi major axis is given by Kepler's third law. Its mathematical form is given by :

$T^2=\dfrac{4\pi ^2}{GM}a^3$

G is universal gravitational constant

M is solar mass

Plugging all the values,

$T^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.98\times 10^{30}}\times (4\times 10^{12})^3\\\\T=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.98\times10^{30}}\times(4\times10^{12})^{3}}\\\\T=4.37\times 10^9\ s$

Since,

$1\ s=3.17\times 10^{-8}\ \text{years}\\\\4.37\times 10^9\ s=4.37\cdot10^{9}\cdot3.17\cdot10^{-8}\\\\4.37\times 10^9\ s=138.52\ \text{years}$

So, the orbital period of a dwarf planet is 138.52 years.

3 0

3 years ago

Suppose you had two magnets, who were attracted to each other, and you brought them together. Then took them apart by separating

IgorLugansk [536]

Answer:4. Two charged objects have a repulsive force of 0.080 N. If the distance separating the objects is tripled, then what is the new force? Explanation: The electrostatic force is inversely related to the square of the separation distance.

Explanation:

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2 years ago