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Anna71 [15]
2 years ago
15

Come People join meet let's enjoythis is the code to join meetpjv-ngby-iir​

Chemistry
1 answer:
stira [4]2 years ago
3 0

Answer:

no

Explanation:

<3

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A 200.0 mL solution of 0.40 M ammonium chloride was titrated with 0.80 M sodium hydroxide. What was the pH of the solution after
choli [55]

Answer:

9.25

Explanation:

Let first find the moles of NH_4Cl and NaOH

number of moles of NH_4Cl = 0.40  mol/L × 200 ×  10⁻³L

= 0.08 mole

number of moles of NaOH = 0.80  mol/L × 50 ×  10⁻³L

= 0.04 mole

The equation for the reaction is expressed as:

NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

The ICE Table is shown below as follows:

                            NH^+_{4(aq)} \ + OH^-_{(aq)} ------> NH_{3(g)} \ + H_2O_{(l)}

Initial (M)              0.08            0.04                            0

Change (M)         - 0.04          -0.04                          + 0.04

Equilibrium (M)      0.04             0                                0.04

K_a*K_b = 10^{-14} \ at \ 25^0C

K_a = \frac{10^{-14}}{K_b}

K_a = \frac{10^{-14}}{1.76*10^{-5}}

K_a= 5.68*10^{10}

pK_a = - log \ (K_a)

pK_a = - log \ (5.68*10^{-10})

pK_a = 9.25

pH = pKa + \ log (\frac{HB}{HA} )   for buffer solutions

pH = pKa + \ log (\frac{moles \ of \ base }{ moles\ of \ acid} ) since they are in the same solution

pH = 9.25 + \ log (\frac{0.04 }{ 0.04} )

pH = 9.25

8 0
3 years ago
What is the section of lithosphere that carries crust
Tanya [424]
The best answer that I can give you is, the Plate.
6 0
3 years ago
What is the empirical formula of a compound that is made of 3.80g of phosphorus and 0.371g of hydrogen?
lys-0071 [83]

You start by diving each quantity given by the atomic wight of each element:

Phosphorus (P)   \frac{3.8}{31} =0.123

Hydrogen (H)   \frac{0.371}{1} =0.371

Then you divide by the lowest number:

\frac{0.123}{0.123} = 1 for phosphorus

\frac{0.371}{0.123} = 3 for hydrogen

So the empirical formula will be:    

PH_{3}

6 0
3 years ago
What is a polar liquid?
BabaBlast [244]
Polar liquids have both negative and positive ends.
3 0
3 years ago
Read 2 more answers
The reaction H2SO4 + 2 NaOH -&gt; Na2SO4 + 2H2O represents an acid-base tritration. The equivalence point occurs when 24.75 mL o
artcher [175]
            moles NaOH = c · V = 0.2432 mmol/mL · 24.75 mL = 6.0192 mmol
            moles H2SO4 = 6.0192 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.0096 mmol
Hence
            [H2SO4]= n/V = 3.0096 mmol / 38.94 mL = 0.07729 M
The answer to this question is  [H2SO4] = 0.07729 M

6 0
3 years ago
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