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3 years ago

PLEASE HELP ME

2 answers:

4 0

The answer is B. Vas deferens.

The Vas deferens is a tube that carries the sperm from your testes to the urethra and out the body. A vasectomy is a form of birth control where the pathway of sperm is blocked through cutting or tying off the vas deferens. The word Vasectomy comes from the term Vas<span> deferens.</span>

arsen [322]3 years ago

3 0

Answer: Vas deference

Explanation: This is a method of contraception in uses a small surgical procedure. This method is a permanent method of contraception.

During this procedure, male vas deference are cut and tied together or we can say it is sealed to prevent the path of sperm from getting into the urethra and in this way it prevents fertilization of a females egg during the sexual intercourse.

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The following are connected in parallel circuit at home EXCEPT:

nikdorinn [45]

Light bulbs, think about parallel circuits as something you plug into, so for example you plug in a tv for it to work, same with a refrigerator and Christmas lights

8 0

2 years ago

The intensity of light from a star (its brightness) is the power it outputs divided by the surface area over which it’s spread:

kow [346]

Answer:

$\frac{d_{1}}{d_{2}}=0.36$

Explanation:

1. We can find the temperature of each star using the Wien's Law. This law is given by:

$\lambda_{max}=\frac{b}{T}=\frac{2.9x10^{-3}[mK]}{T[K]}$ (1)

So, the temperature of the first and the second star will be:

$T_{1}=3866.7 K$

$T_{2}=6444.4 K$

Now the relation between the absolute luminosity and apparent brightness is given:

$L=l\cdot 4\pi r^{2}$ (2)

Where:

L is the absolute luminosity
l is the apparent brightness
r is the distance from us in light years

Now, we know that two stars have the same apparent brightness, in other words l₁ = l₂

If we use the equation (2) we have:

$\frac{L_{1}}{4\pi r_{1}^2}=\frac{L_{2}}{4\pi r_{2}^2}$

So the relative distance between both stars will be:

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{L_{1}}{L_{2}}$ (3)

The Boltzmann Law says, $L=A\sigma T^{4}$ (4)

σ is the Boltzmann constant
A is the area
T is the temperature
L is the absolute luminosity

Let's put (4) in (3) for each star.

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{A_{1}\sigma T_{1}^{4}}{A_{2}\sigma T_{2}^{4}}$

As we know both stars have the same size we can canceled out the areas.

$\left(\frac{d_{1}}{d_{2}}\right)^{2}=\frac{T_{1}^{4}}{T_{2}^{4}}$

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{T_{1}^{4}}{T_{2}^{4}}}$

$\frac{d_{1}}{d_{2}}=0.36$

I hope it helps!

5 0

3 years ago

True or false: (a) Maxwell's equations apply only to fields that are constant over time.(b) The wave equation can be derived fro

Andre45 [30]

Answer:

(a) False

(b) True

(d) True

(e) True

(f) True

Explanation:

(a) Maxwell's equations not only applies to constant fields but it applies to both the fields, i.e., Time variant field as well as Time Invariant field.

(b) We make use of the Modified form of the Ampere's law and Faraday's Law to derive the wave equation.

(c) Electromagnetic waves contains both the electric and magnetic fields and these fields oscillates at an angle of $90^{\circ}C$ to the direction of wave propagation.

(d) In free space both the electric and magnetic fields are in phase while considering electromagnetic waves.

(e) In free space or vacuum, the expression for the speed of light in terms of electric and magnetic field is given as:

$c = \frac{E}{B}$

Thus the ratio of the magnitudes of the electric and magnetic field vectors are equal to the speed of light in free space.

(f) In free space or in vacuum the energy density of the electromagnetic wave is divided equally in both the fields and hence are equal.

3 0

3 years ago

Muscular strength is BEST described by

oee [108]

The answer is C. Muscular strength is the force produced in a single maximum effort.

7 0

3 years ago

A metal block of mass 265 g rests at a point 2.4 m from the center of a horizontal rotating wooden platform. The coefficient of

FrozenT [24]

Answer:

The minimum angular velocity of the platform what whould the block slides away is w= 2.26 rad/s.

Explanation:

m= 0.265 kg

r= 2.4 m

μ= 0.257

g= 9.8 m/s²

W= m * g

W= 2.597 N

Fr= μ * W

Fr= 0.66 N

∑F = m * ac

W+Fr = m * ac

(W+ Fr) / m = ac

ac= 12.29 m/s²

ac= w² * r

√(ac/r)= w

w= 2.26 rad/s

3 0

3 years ago