Answer:
0.82 m/s
Explanation:
From the law of conservation of momentum,
Total momentum = Final momentum.
mu+m'u' = V(m+m')......................... equation 1
Where m = mass of Lillian, u = initial velocity of Lillian before she catches the dog, m' = mass of the dog, u' = initial velocity of the dog, V = velocity of Lillian and the dog.
make V the subject of the equation,
V = (mu+m'u')/(m+m')................ Equation 2
Given: m = 40 kg, m' = 15 kg, u = 0 m/s (Lillian was standing at rest), u' = 3.0 m/s.
Substitute into equation 2
V = (40×0+15×3)/(40+15)
V = (0+45)/55
V = 45/55
V = 0.82 m/s
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Prokaryote: prokaryotes were the earliest living organisms which are unicellular having a primitive nucleus i.e they don’t have a true nucleus
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Answer:
The top of the window is 0.5 m below the sill of the upper window
Explanation:
We have the time the pot takes to fall a distance y- yo = 2.0 m and g = 9.8, from this we can calculate the velocity of the pot when it just reached the top of the window in question. Take the positive y direction to be downward
y-yo=vo*t+I/2gt^2
vo=(y-yo-I/2gt^2)/t
vo=3.138 m/s
The flowerpot falls from rest and we have the velocity it gains until it reaches the top of the window below, from this information we can get the distance between the sill and the top of the window below.
v^2=vo^2+2g(y-yo)
y-yo=(v^2-vo^2)/2g
= 0.5 m
The top of the window is 0.5 m below the sill of the upper window
Answer:
The speed of the center of mass of the two carts is 0.103 m/s
Explanation:
It is given that,
Mass of the air track cart, m₁ = 350 g = 0.35 kg
Velocity of air track cart, v₁ = 1.25 m/s
Mass of cart, m₂ = 280 g = 0.28 kg
Velocity of cart, v₂ = -1.33 m/s (it is travelling in opposite direction)
We need to find the speed of the center of mass of the two carts. It is given by the following relation as :
Hence, this is the required solution.
