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s344n2d4d5 [400]
3 years ago
15

A car moving at 50 km/h skids 15 m with locked brakes. How far will the car skid with locked brakes at 150 km/h

Physics
2 answers:
Zanzabum3 years ago
7 0

with 50 km/h = 15m skid

so, 150 km/h = 45m skid

multiply sides by 3, make them proportional to each other!!!

Jobisdone [24]3 years ago
7 0
Kinetic energy = (1/2 m) x (speed)²

A car moving 3 times as fast has 9 times as much kinetic energy.

If the force of friction between the tires and the ground
is the same at every speed, then the car has to go 9 times
as far to burn off the increased kinetic energy.

    9 x 15m  =  135 meters
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Explain why materials such as plastic foam, feathers, and fur are poor conductors of heat.
Firlakuza [10]
The atoms of some materials have no free electrons in their outer orbits. These electrons are busy doing other jobs, like being shared in the orbits of two adjacent atoms. They are so closely held that it is very difficult to pull them away. Most compounds of carbon and hydrogen are like this. 

<span>Plastics, whose molecules are made from long combinations of carbon and hydrogen atoms, have few or no free electrons. This means that plastics are poor conductors of electricity (and they are also poor conductors of heat). hope that helped.</span>
7 0
3 years ago
A body falls from the top of the tower and during the last second of its fall it fall through 23mvfind height of tower.
DanielleElmas [232]

Answer:

39.7 m

Explanation:

First, we conside only the last second of fall of the body. We can apply the following suvat equation:

s=ut+\frac{1}{2}at^2

where, taking downward as positive direction:

s = 23 m is the displacement of the body

t = 1 s is the time interval considered

a=g=9.8 m/s^2 is the acceleration

u is the velocity of the body at the beginning of that second

Solving for u, we find:

ut=s-\frac{1}{2}at^2\\u=\frac{s}{t}-\frac{1}{2}at=\frac{23}{1}-\frac{1}{2}(9.8)(1)=18.1 m/s

Now we can call this velocity that we found v,

v = 18 m/s

And we can now consider the first part of the fall, where we can apply the following suvat equation:

v^2-u^2 = 2as'

where

v = 18 m/s

u = 0 (the body falls from rest)

s' is the displacement of the body before the last second

Solving for s',

s'=\frac{v^2-u^2}{2a}=\frac{18.1^2-0}{2(9.8)}=16.7 m

Therefore, the total heigth of the building is the sum of s and s':

h = s + s' = 23 m + 16.7 m = 39.7 m

7 0
3 years ago
Why might the 1990 earthquake and volcanic eruption in Luzon be related?
Art [367]
I am  not sure but i think the answer is C
6 0
3 years ago
Can you help me on this fast just the second one
Mariulka [41]
4. E
5. D
6. F

Hope this helps
3 0
3 years ago
In the graph, which region shows nonuniform positive acceleration?
cricket20 [7]

Answer: A.AB

Explanation:

This Velocity vs Time graph shows the acceleration of a body or object, since acceleration is the variation of velocity in time.

As we can see in the attached image, the graph can be divided in four segments:

OA: In this segment the acceleration is changing at a uniform rate. In addition we can see it has a positive slope, hence we are dealing with a positive uniform acceleration.

AB: In this segment the acceleration is changing at a nonuniform rate, since  in this part it is not possible to calculate the slope. However if this were uniform, the slope woul be positive. This means the <u>acceleration is nonuniform and positive.</u>

BC: In this segment the acceleration is changing at a nonuniform rate, since  in this part it is not possible to calculate the slope. However if this were uniform, the slope woul be negative. This means the acceleration is nonuniform and negative.

CD: In this segment the acceleration is changing at a uniform rate. In addition we can see it has a negative slope, hence we are dealing with a negative uniform acceleration.

From all these segments, the only one that fulfils the nonuniform positive acceleration condition is option A:

Segment AB

3 0
2 years ago
Read 2 more answers
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