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s344n2d4d5 [400]
3 years ago
15

A car moving at 50 km/h skids 15 m with locked brakes. How far will the car skid with locked brakes at 150 km/h

Physics
2 answers:
Zanzabum3 years ago
7 0

with 50 km/h = 15m skid

so, 150 km/h = 45m skid

multiply sides by 3, make them proportional to each other!!!

Jobisdone [24]3 years ago
7 0
Kinetic energy = (1/2 m) x (speed)²

A car moving 3 times as fast has 9 times as much kinetic energy.

If the force of friction between the tires and the ground
is the same at every speed, then the car has to go 9 times
as far to burn off the increased kinetic energy.

    9 x 15m  =  135 meters
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3 years ago
The graph shows the amplitude of a passing wave over time in seconds (s). What is the approximate frequency of the wave shown?
belka [17]

Answer:

B) 0.3Hz

Explanation:

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7 0
3 years ago
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Draw a schematic diagram of a circuit consisting of a battery of five 2 V cells, a 5 ohm resistor, a 10 ohm resistor, a 15 ohm r
MakcuM [25]

Answer:

  • Current = 0.33 A

Explanation:

  • For diagram refer the attachment.

It is given that five cells of 2V are connected in series, so total voltage of the battery:

\dashrightarrow \: \:  \sf V = 2 \times 5 = 10 V

Three resistor of 5\Omega, 10\Omega, 15\Omega are connected in Series, so the net resistance:

\dashrightarrow \: \: \sf R_{n} = R_{1} + R_{2} + R_{3}

\dashrightarrow \: \:  \sf R = 5 + 10 + 15

{ \pink{\dashrightarrow \sf \: \: { \underbrace{R = 30 \:  \Omega}}}}

According to ohm's law:

\dashrightarrow  \sf\: \: V = IR

\dashrightarrow  \sf \: \: I = \dfrac{V}{R}

On substituting resultant voltage (V) as 10 V and resultant resistant, as 30 {\pmb{\sf{\Omega}}} we get:

\dashrightarrow \sf \: \: I = \dfrac{10V}{30\Omega}

{ \pink{\dashrightarrow \sf \: \: { \underbrace{I = 0.33 A}}}}

\thereforeThe electric current passing through the above circuit when the key is closed will be <u>0.33 A</u>

4 0
2 years ago
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an 11 kg tool box is floating stationary in an orbiting spacecraft when a 79 kg astronaut, initially at rest, gives the tool box
snow_tiger [21]

The astronaut final velocity is 0.06 m/s to the right

Explanation:

In absence of external forces, the total momentum of the box-astronaut system is conserved.

At the beginnig, the total momentum of the two is zero, since they are at rest:

p_i = 0

While the final momentum, after the astronaut throws the box, is:

p_f=mv+MV

where

m = 11 kg is the mass of the box

M = 79 kg is the mass of the astronaut

v = -0.45 m/s (to the left) is the velocity of the box (we take left as negative direction)

V is the final velocity of the astronaut

The total momentum is conserved, so

p_i = p_f\\0=mv+MV

And solving , we find V:

V=-\frac{mv}{M}=-\frac{(11)(-0.45)}{79}=0.06 m/s

And the positive sign indicates that the direction is to the right.

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6 0
3 years ago
A body travels 30m in 5s, 45m in 7s and then 65m in the last 5s. Find the average speed of the body
JulijaS [17]
We can find the average speed of the body by finding the total distance covered, and then dividing it by the total time of the motion.

The total distance covered is:
S=30 m + 45m+65m=140 m

while the total time of the motion is
t=5 s+7s+5 s=17 s

So, the average speed of the body is:
v= \frac{S}{t}= \frac{140 m}{17 s}=8.24 m/s
8 0
3 years ago
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