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maksim [4K]
3 years ago
9

This experiment, you compare several unknown powders to known powders. What is the name given to all of the known materials used

for comparison in this experiment?
A.quantities
B.controls
C.constants
D.variables
Physics
2 answers:
Neporo4naja [7]3 years ago
8 0

the correct answer is B .Controls

brilliants [131]3 years ago
5 0
<span>B. Controls: The known powders attributes are already studied, so the are used as control measures to compare with the findings in the experiment with the unknown powders.</span>
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What would most likely happen as a result of the generator in a wind turbine breaking? The blades would not be turned. Less stea
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Answer:

What would most likely happen as a result of the generator in a wind turbine breaking?

The What would most likely happen as a result of the generator in a wind turbine breaking?

The blades would not be turned.

Less steam would be produced.

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Solar energy would not be absorbed.

The blades would not be turned.

Less steam would be produced.

Electricity would not be generated.

Solar energy would not be absorbed.

Explanation:

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3 years ago
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A car is traveling at a speed of 10m/s. A 0.5kg clump of mudis
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Answer:B

Explanation:

Given

speed of car v=10 m/s

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Since the tire is rotating about axle so a centripetal force is acting constantly on each particle towards the center of tire.

Centripetal force is given by

F_c=\frac{mv^2}{r}

where m=mass\ of\ element

v=speed

r=distance\ from\ center

F_c=\frac{0.5\times 10^2}{0.2}

F_c=250\ N (inward)

           

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3 years ago
What is the speed of a wave in (m/s) with a 5 meter wavelength and a period of 20 seconds?
arlik [135]

Answer: 0.25 m/s

Explanation:  Speed = wavelengt · frequency  

v = λf   and frequency is 1/period  f = 1/T

Then v = λ/T = 5 m / 20 s = 0.25 m/s

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3 years ago
a ball of mass 0.5 kg moving at 10 m/s collides with another ball of equal mass at rest. if the two balls move off together afte
nexus9112 [7]

Answer:

5 m/s

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7 0
3 years ago
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kondaur [170]

Answer with Explanation:

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F=\frac{1}{4\pi \epsilon _o}\frac{q_1\times q_2}{r^2}=k\frac{q_1\times q_2}{r^2}

where

\epsilon _o is a constant known as permitivity of free space

k=9\times 10^{9}Nm^2/C^2

Applying the given values in the above relation we get

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3 years ago
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