4 years ago

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Physics

1 answer:

zavuch27 [327]4 years ago

6 0

Yes I pretty sure it's c

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A 6.50 meter high cylinder is filled with alcohol(density =806 kg/m^3). What is the pressure at the bottom of the cylinder?

makvit [3.9K]

Answer:

152642.2

Explanation:

the pressure at the bottom of the cylinder is

P = Po + rho gh

=101300+806(9.8)(6.5)

=152642.2 Pa

3 0

3 years ago

if the motor in a geared appliance has a rated speed of 3600 rpm and a gear ratio of 6 to 1 the driven gear will turn at speed o

sergeinik [125]

3600/6/1= 600rpm. Higher torque, lower speed

7 0

3 years ago

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At depths of greater than 60 m, ice moves by plastic deformation. What causes this transition from brittle to ductile behavior?

mafiozo [28]

Answer:

Increase in the intensity of pressure allows very less deformation

Explanation:

For the water the variation of pressure at any depth is directly proportional to the depth of the water above that level.

Thus, at depth greater than 60 m the intensity of pressure on ice is very high and therefore very little deformation is possible.

Hence, the transition from brittle to ductile behavior is observed.

3 0

4 years ago

A thin-walled vessel of volume V contains N particles which slowly leak out of a small hole of area A. No particles enter the vo

LuckyWell [14K]

Answer:

$\frac{V}{2av}$

Explanation:

From the question we are told that

Volume V

Contains N particles

Leaks from a small hole of area A

Generally the equation for Flow rate is given as

Volume Flow Rate $V_r = A * v$

Mathematically we find the time taken to flow half way which is given by

$\frac{(V/2)}{A*v}$

Therefore the time taken is

$\frac{V}{2av}$

7 0

3 years ago

will the value of g be affected by the radius of the earth? consider the real shape of the earth. compare the acceleration due t

sp2606 [1]

Answer:

Yes, the value of g affected by the radius.

Explanation:

The formula for the force of gravity of 2 objects is

$F_{gravity} = G\frac{m_{1}m_{2}}{r^2}$ , where m1 and m2 are the masses of the 2 objects, r is the radius, and G is the gravitational constant, which is approximately $6.67 \cdot 10^{-11}$ .

Therefore, as the radius if bigger, the force of gravity is going to be smaller exponentially.

5 0

4 years ago