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kondor19780726 [428]
3 years ago
14

Tony uses the device shown in the diagram to model how an electromagnet is used in his uncle’s scrap metal yard. After picking u

p several staples with the device, what change would enable Tony to drop the staples in the scrap metal bin?
Removing the battery
removing the iron nail
moving the wire loops closer together
spreading the wire loops farther apart
Physics
2 answers:
marusya05 [52]3 years ago
8 0
An electromagnet is a device which uses a current and passes this through a conductor. The current induces a magnetic field in the conductor, making the conductor a magnet. In order to remove the effects of this magnetism, the device may have its electrical power cut off. Therefore, the way to drop the staples in the bin would be to remove the battery.
PolarNik [594]3 years ago
7 0

for the ones on edge its a

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How does the electric force between two charged particles change if the distance between them is increased by a factor of 2
mart [117]
Electric force will increase
6 0
3 years ago
g The current through a 10 m long wire has a current density of 4 cross times 10 to the power of 6 space open parentheses bevell
olga55 [171]

Answer:

The value is V  =  2 V

Explanation:

From the question we are told that

The length of the wire is l = 10 \ m

The current density is J =  4*10^6 \  A/m^2

The conductivity is \sigma  =  2*10^{7} \  S/m

Generally conductivity is mathematically represented as

\sigma  =  \frac{l}{RA}

Here R is the resistance which is mathematically represented as

R =  \frac{V}{I}

Here I is the current which is mathematically represented as

I  =  J * A

So

R =  \frac{V}{  J * A}

And

\sigma  =  \frac{l}{\frac{V}{  J * A} * A}

=> \sigma  =  \frac{l}{\frac{V}{J}}

=> V = \frac{l * J}{\sigma }

=> V = \frac{10  * 4*10^6}{2*10^{7}  }

=> V  =  2 V

5 0
3 years ago
Problem: The frequency of an FM radio station is 89.3 MHz. Calculate its period. Part B: From the Library, select the general eq
vekshin1

Answer:

Time period, T=1.11\times 10^{-8}\ s

Explanation:

We have,

The frequency of an FM radio station is 89.3 MHz.

It is required to find the period of the wave.

The reciprocal of frequency is called time period of a wave. It can be given by :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{89.3\times 10^{6}\ Hz}\\\\T=1.11\times 10^{-8}\ s

So, the period of the wave is 1.11\times 10^{-8}\ s.

5 0
3 years ago
The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?
BigorU [14]

1. Frequency: 7.06\cdot 10^{14} Hz

The frequency of a light wave is given by:

f=\frac{c}{\lambda}

where

c=3\cdot 10^{-8} m/s is the speed of light

\lambda is the wavelength of the wave

In this problem, we have light with wavelength

\lambda=425 nm=425\cdot 10^{-9} m

Substituting into the equation, we find the frequency:

f=\frac{c}{\lambda}=\frac{3\cdot 10^{-8} m/s}{425\cdot 10^{-9} m}=7.06\cdot 10^{14} Hz


2. Period: 1.42 \cdot 10^{-15}s

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

The frequency of this light wave is 7.06\cdot 10^{14} Hz (found in the previous exercise), so the period is:

T=\frac{1}{f}=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s


4 0
3 years ago
Read 2 more answers
What is the volume of a cube with length = 3 centimeters, width = 3
suter [353]

Answer:

D. 27 cubic centimeters

Explanation:

l*w*h

3*3*3= 27

4 0
3 years ago
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