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Dmitry [639]
3 years ago
14

A solenoid 0.425 m long has 950 turns of wire. What is the magnetic field in the center of the solenoid when it carries a curren

t of 2.75 A? (JC 19.57)
Physics
1 answer:
lesya692 [45]3 years ago
4 0

Answer:

The magnetic field in the center of the solenoid is 7.8\times10^{-3}\ T.

Explanation:

Given that,

Length of solenoid = 0.425 m

Number of turns N = 950

Current I = 2.75 A

The magnetic field in the center of the solenoid is the product of the current , number of turns per unit length and permeability.

In mathematical form,

B = \mu_{0}nI

Where, n = \dfrac{N}{l}

N = number of turns

L = length

I = current

Now, The magnetic field

B = \dfrac{\mu_{0}NI}{l}

Put the value into the formula

B=\dfrac{4\pi\times10^{-7}\times950\times2.75}{0.425}

B=\dfrac{4\times3.14\times10^{-7}\times950\times2.75}{0.425}

B=7.8\times10^{-3}\ T

Hence, The magnetic field in the center of the solenoid is 7.8\times10^{-3}\ T.

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Two point charges, 1.8 pC and −1.8 pC, are separated by 7 µm. What is the dipole moment of this pair of charges?
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Answer: 12,600,000Cm

Explanation:

From the data's;

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2 years ago
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Answer:

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Gelneren [198K]
Hello,

The answer should be option D "specific heat".

Reason:

Specific heat is what tells the person how my heat and or pressure is required to raised the objects temperature. Its not option A convection because I'm convection is mainly used as like the ozone layer and the suns rays. Its not option B radiation because radiation doesn't tell the person what temperature it needs in order for it to rise its more like its already rises and hot. Its also not option C because conduction is the process of a object heating another object therefore the answer is option D.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
5 0
3 years ago
Read 2 more answers
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