Answer:
4.53482 m/s
4.506 m/s
Explanation:
= Mass of player = 75 kg
= Initial velocity of player = 4.6 m/s
= Mass of ball = 0.47 kg
= Initial velocity of ball = 15 m/s
The linear momentum of the system is conserved

The player's speed is 4.53482 m/s
In the second case the equation of momentum is

The player's speed is 4.506 m/s
Answer:
(a) The motion is uniform
(b) 11.11 m/s
Explanation:
(a)
From the table below, the motion of the bus is uniform.
(b)
Speed(s) = Δd/Δt
s = Δd/Δt............. Equation 1
From the table,
Given: Δd = 10 km = 10000 m, Δt = 15 minutes = (15×60) = 900 seconds
Substitute these values into equation 1
s = 10000/900
s = 11.11 m/s
Answer:31.62 m/s
Explanation:
Given
mass of body 
Pull on chain is 
Pull get smaller at the rate of 
Net Upward Force 
net acceleration 



but g is acting downward

using 
here initial velocity is zero


Answer:
Eleven seconds.
Explanation:
Two keys are needed to solve this problem. First, the conservation of momentum: allowing you to calculate the cart's speed after the elephant jumped onto it. It holds that:

So, once loaded with an elephant, the cart was moving with a speed of 4.29m/s.
The second key is the kinematic equation for accelerated motion. There is one force acting on the cart, namely friction. The friction acts in the opposite direction to the horizontal direction of the velocity v0, its magnitude and the corresponding deceleration are:

The kinematic equation describing the decelerated motion is:

It takes 11 seconds for the comical elephant-cart system to come to a halt.
Answer: tu dia es INCORRECTO
Explanation: