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Anarel [89]
3 years ago
7

The fact that desert sand is very hot in the day and very cold at night is evidence that sand has

Physics
2 answers:
insens350 [35]3 years ago
5 0

Answer:

A) a low specific heat.

Explanation:

As we know that heat given to the sand will increase it temperature

so we can say

Q = ms\Delta T

here we will have

\Delta T = \frac{Q}{ms}

so now we will have

more change in temperature due to heat given to the sand will show that it must have low specific heat capacity as it inversely depends on the specific heat capacity of the sand

so correct answer will be

A) a low specific heat.

4vir4ik [10]3 years ago
4 0

The fact that desert sand is very hot in the day and very cold at night is evidence that sand has  

A) a low specific heat. Answer: A

Explanation: Because the fact that desert sand is very hot in the day and very cold at night is evidence that sand has  

A) a low specific heat.

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The region under the speed time chart gives the relocation.  

In simple to-recall, straightforward terms, remove levels with the result of speed and time. So when you discover the region under a speed time diagram, you are really increasing speed and time. This gives the separation.

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What is Law of gravitation?
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The four living things seen here, dog, flower, algae, and bacteria, are all made of cells. A - C are multicellular, but D is uni
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3 years ago
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Q1 is located at the origin, Q2 is located at x = 2.50 cm and Q3 is located at x = 3.50 cm. Q1 has a charge of +4.92μC and Q3 ha
Inessa05 [86]

Answer:

+1.11\mu C

Explanation:

A charge located at a point will experience a zero electrostatic force if the resultant electric field on it due to any other charge(s) is zero.

Q_1 is located at the origin. The net force on it will only be zero if the resultant electric field intensity due to Q_2 and Q_3 at the origin is equal to zero. Therefore we can perform this solution without necessarily needing the value of Q_1.

Let the electric field intensity due to Q_2 be +E_2 and that due to Q_3 be -E_3 since the charge is negative. Hence at the origin;

+E_2-E_3=0..................(1)

From equation (1) above, we obtain the following;

E_2=E_3.................(2)

From Coulomb's law the following relationship holds;

+E_2=\frac{kQ_2}{r_2^2}\\  

-E_3=\frac{kQ_3}{r_3^2}

where r_2 is the distance of Q_2 from the origin, r_3 is the distance of Q_3 from the origin and k is the electrostatic constant.

It therefore means that from equation (2) we can write the following;

\frac{kQ_2}{r_2^2}=\frac{kQ_3}{r_3^2}.................(3)

k can cancel out from both side of equation (3), so that we finally obtain the following;

\frac{Q_2}{r_2^2}=\frac{Q_3}{r_3^2}................(4)

Given;

Q_2=?\\r_2=2.5cm=0.025m\\Q_3=-2.18\mu C=-2.18* 10^{-6}C\\r_3=3.5cm=0.035m

Substituting these values into equation (4); we obtain the following;

\frac{Q_2}{0.025^2}=\frac{2.18*10^{-6}}{0.035^2}\\\\hence;\\\\Q_2=\frac{0.025^2*2.18*10^{-6}}{0.035^2}\\

Q_2=\frac{0.00136*10^{-6}}{0.00123}=1.11*10^{-6}C\\\\Q_3=+1.11\mu C

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2 years ago
Jasper and Gemma are going to play on a teeter totter. Gemma gets on first. When Jasper gets on, Gemma moves into the air, but s
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Answer:

it will most likely be a: the forces are balanced because jasper weighs the same as gemma.

Explanation:

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