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Andrei [34K]
4 years ago
9

At which temperature does the motion of atoms and molecules stop?

Physics
2 answers:
Charra [1.4K]4 years ago
5 0

At which temperature does the motion of atoms and molecules stop?

0°C

0 C

0°K

0 K

it would be 0 K

Aleks [24]4 years ago
3 0
Absolute Zero, hopefully that helps :)
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What is used to measure mass?
defon

Answer:

A balance

Explanation:

Scientists measure mass with a balance, such as a triple beam balance or electronic balance. In science, the volume of a liquid might be measured with a graduated cylinder.

4 0
3 years ago
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How is it possible for two objects to have the same momentum but different velocities give an example
castortr0y [4]
Momentum is
p = mv, where m is the mass and v is the speed.
So, if two objects have the same momentum but different speeds, the must have different masses as well.
v1/v2 = m2/m1
The example is a car and a truck. Car has the mass 1000 kg and velocity 100 m/s, and truck has the mass 5000 kg and velocity 20 m/s. Use the formula above to determine is it true that they have the same momentum:
(100 m/s) / (20 m/s) = (5000 kg) / (1000 kg)
5 = 5
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Hope this helps! Good luck!
4 0
3 years ago
A heating element has a resistance of 180 Ω and draws a current of 1.60 A. What is its power?
iragen [17]

its either 288Watts or 112.5 Watts

5 0
3 years ago
Read 2 more answers
In the United States, household electric power is provided at a frequency of 60 HzHz, so electromagnetic radiation at that frequ
grigory [225]

Answer:

the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Explanation:

Given the data in the question;

To determine the maximum intensity of an electromagnetic wave, we use the formula;

I = \frac{1}{2}ε₀cE_{max²

where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )

c is the speed of light ( 3 × 10⁸ m/s )

E_{max is the maximum magnitude of the electric field

first we calculate the maximum magnitude of the electric field ( E_{max  )

E_{max = 350/f kV/m

given that frequency of 60 Hz, we substitute

E_{max = 350/60 kV/m

E_{max = 5.83333 kV/m

E_{max = 5.83333 kV/m × ( \frac{1000 V/m}{1 kV/m} )

E_{max = 5833.33 N/C

so we substitute all our values into the formula for  intensity of an electromagnetic wave;

I = \frac{1}{2}ε₀cE_{max²

I = \frac{1}{2} × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²

I = 45 × 10³ W/m²

I = 45 × 10³ W/m² × ( \frac{1 kW/m^2}{10^3W/m^2} )

I = 45 kW/m²

Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

7 0
3 years ago
A force of 125 N is applied to a 50 kg. Mass. What is the acceleration of the mass?
grandymaker [24]
The acceleration would be 2.5 m/sec^2
A= acceleration
F= force
M= mass
A = f/m
125N/50kg=2.5 m/s^2
3 0
4 years ago
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