Ask question

Ask question

All categories

3 years ago

9

At which temperature does the motion of atoms and molecules stop?

2 answers:

Charra [1.4K]3 years ago

5 0

At which temperature does the motion of atoms and molecules stop?

0°C

0 C

0°K

0 K

it would be 0 K

Aleks [24]3 years ago

3 0

Absolute Zero, hopefully that helps :)

You might be interested in

Choose the type of literary device being used in the example below. I ran as fast as a cheetah but I still missed the bus, which

Feliz [49]

Simile, as the example compares the person with a cheetah using “as” (a simile uses “like” or “as” for comparisons between two things).

5 0

3 years ago

You observe a spiral galaxy with a large central bulge and tightly wrapped arms. It would be classified a

miv72 [106K]

Answer:

Sa

Explanation:

Spiral Galaxies -

It is a disk shaped galaxies which have spiral structure , is refereed to as spiral galaxies .

According to Hubble , these galaxies are classified as Sa , Sb , Sc .

Where ,

Sa - have the structure , which is bulged from the central portion , along with a tightly wrapped spiral structure .

Sb - have a lesser bulge and the spiral is looser .

Sc - It has very weak bulge with the open spiral structure .

Hence , from the question ,

The given information is about the Sa .

6 0

3 years ago

A suspension bridge has twin towers that are 1300 feet apart. Each tower extends 180 feet above the road surface. The cables are

zhannawk [14.2K]

Answer:

$y = 17.04 ft$

Explanation:

Since the cable touches the road at the mid point of two towers

so here we have vertex at that mid point taken to be origin

now the maximum height on the either side is given as

$y = 180 ft$

horizontal distance of the tower from mid point is given as

$x = \frac{1300}{2} = 650 ft$

now from the equation of parabola we have

$y = k x^2$

$180 = k(650^2)$

$k = 4.26 \times 10^{-4}$

now we have

$y = (4.26 \times 10^{-4})x^2$

now we need to find the height at distance of 200 ft from center

so we have

$y = (4.26 \times 10^{-4})(200^2)$

$y = 17.04 ft$

8 0

3 years ago

A rod of length L and electrical resistance R moves through a constant uniform magnetic field ; both the magnetic field and the

CaHeK987 [17]

Answer:

don't know what class are you you are using which mobile or laptop

6 0

3 years ago

The electric flux through a spherical surface is 1.4 ✕ 105 N · m2/C. What is the net charge (in C) enclosed by the surface?

Anit [1.1K]

Answer:

The value is $Q_{net} = 1.239 *10^{-6} \ C$

Explanation:

From the question we are told that

The electric flux is $\Phi = 1.4*10^{5} \ N\cdot m^2/C$

Generally the net charge is mathematically represented as

$Q_{net} = \Phi * \epsilon_o$

Here $\epsilon_o$ is the permetivity of free space with value

$\epsilon_o = 8.85*10^{-12} \ \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2$

So

$Q_{net} = 1.4*10^5 * 8.85*10^{-12}$

=> $Q_{net} = 1.239 *10^{-6} \ C$

8 0

3 years ago