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riadik2000 [5.3K]
2 years ago
8

How many grams of water will I obtain from the combustion of 0.9249 mol of pentane (C5H12) in the following reaction?

Chemistry
2 answers:
pshichka [43]2 years ago
8 0

Answer:

C5H12 + 8 (O2) --> 5 (CO2) + 6 (H2O)

*Molar Ratio of Pentane and water is 1:6

*Number of mol of H2O = 0.9249 ×6 = 5.5494 mol

* Molar mass of H2O = 18 g/mol

* Mass of H2O needded = 5.5494 mol × 18 g/mol

= 99.8892 g

Explanation:

* By balancing the equation we can get the stiochemetry of the reaction (Molar Ratio).

* Then we can find the number of mol of H2O neede relative to the no. of mol of Pentane.

* Multiply the mol of H2O by the molar mass of H2O to get the mass.

VLD [36.1K]2 years ago
5 0

Answer: watch?v=zdAtYbCPSnA

Explanation:Should help

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Calculate the Molecular or Formula massof each of the following:
DiKsa [7]

Explanation:

Molar mass  

The mass present in one mole of a specific species .

The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .

(a) P₄

Molar mass of of the atoms are -

Phosphorous , P = 31 g/mol

Molecular mass of  P₄ = ( 4 * 31 ) = 124 g/mol .

(b) H₂O

Molar mass of of the atoms are -

Hydrogen , H = 1 g/mol

oxygen , O = 16 g/mol.

Molecular mass of H₂O = ( 2 * 1 ) + ( 1 * 16 ) = 18 g/mol

(c) Ca(NO₃)₂

Molar mass of of the atoms are -

calcium , Ca = 40 g/mol

nitrogen, N = 14 g/mol

oxygen , O = 16 g/mol.

Molecular mass of  Ca(NO₃)₂ = ( 1 * 40 ) + ( 2 * 14 ) + ( 6 * 16 ) = 164 g/mol.

(d)CH₃CO₂H (acetic acid)

Molar mass of of the atoms are -

Carbon , C = 12 g/mol.

oxygen , O = 16 g/mol.  

Hydrogen , H = 1 g/mol

Molecular mass of CH₃CO₂H =( 2 * 12 ) + (2 * 16 ) + (4 * 1 ) = 60 g/mol.

(e) C₁₂H₂₂O₁₁ (sucrose, cane sugar).

Molar mass of of the atoms are -

Carbon , C = 12 g/mol.

oxygen , O = 16 g/mol.  

Hydrogen , H = 1 g/mol

Molecular mass of C₁₂H₂₂O₁₁ = (12 * 12 ) + ( 22 * 1 ) + ( 11 * 16 ) = 342 g/mol.

 

4 0
3 years ago
Consider the reaction Mg₂Si(s) + 4 H₂O(ℓ) → 2 Mg(OH)₂(aq) + SiH₄(g). How many grams of silane gas (SiH₄) are formed if 25.0 g of
Neko [114]

Answer:

10.60 grams of silane gas are formed.

Explanation:

From the reaction:

Mg₂Si(s) + 4H₂O(l) → 2Mg(OH)₂(aq) + SiH₄(g)          

We know that the limiting reactant is Mg₂Si, so to find the mass of SiH₄ formed we need to calculate the number of moles of Mg₂Si:

\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}}

Where:

m: is the mass of Mg₂Si = 25.0 g

M: is the molar mass of Mg₂Si = 76.69 g/mol

\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}} = \frac{25.0 g}{76.69 g/mol} = 0.33 moles

Now, the stoichiometric relation between Mg₂Si and SiH₄ is 1:1 so:

\eta_{Mg_{2}Si} = \eta_{SiH_{4}} = 0.33 moles

Finally, the mass of SiH₄ is:

m_{SiH_{4}} = \eta_{SiH_{4}}*M_{SiH_{4}} = 0.33 moles*32.12 g/mol = 10.60 g

Therefore, 10.60 grams of silane gas are formed.

I hope it helps you!    

3 0
3 years ago
What are things animals might do to survive?
ira [324]

Answer:

Ok,for some animals to survive,then ww should first look at the kind of ecosystem they ate exposed to.

So first for some animals to survive,some of them will have to migrate,and so migration in a given set up of an ecosystem,the other animals may lack food as in they depend on the migrating animals as their prey hence their food.

Secondly,hibernation some animals may hibernate due to intensive weather or climate change which is inevitable,and this might affect other animals in such a way that may lead to decrease of their counterparts hence dying due to an imbalance as the other animals may become prey to the predators available.

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What is the chemica composition if the sun
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Vitek1552 [10]
The percent composition of each element can be calculated as follows:
% composition = (mass of element / total mass) * 100

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6 0
3 years ago
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