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2 years ago

How many grams of water will I obtain from the combustion of 0.9249 mol of pentane (C5H12) in the following reaction?

Chemistry

2 answers:

pshichka [43]2 years ago

8 0

Answer:

C5H12 + 8 (O2) --> 5 (CO2) + 6 (H2O)

*Molar Ratio of Pentane and water is 1:6

*Number of mol of H2O = 0.9249 ×6 = 5.5494 mol

* Molar mass of H2O = 18 g/mol

* Mass of H2O needded = 5.5494 mol × 18 g/mol

= 99.8892 g

Explanation:

* By balancing the equation we can get the stiochemetry of the reaction (Molar Ratio).

* Then we can find the number of mol of H2O neede relative to the no. of mol of Pentane.

* Multiply the mol of H2O by the molar mass of H2O to get the mass.

VLD [36.1K]2 years ago

5 0

Answer: watch?v=zdAtYbCPSnA

Explanation:Should help

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It is an ideal gas law based problem. Ideal gas law equation is used to solve this. The equation is:

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Since it asks to calculate the moles that is n, so let's rearrange this for n:

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Let's plug in the values in the equation to get the moles.

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6.32 moles of Fe

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The given chemical equation is presented as follows;

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