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Gnesinka [82]
3 years ago
13

Arrange the bonds between H, O, and F from most polar to least polar based on electronegativity.

Chemistry
1 answer:
Andrews [41]3 years ago
7 0

Answer:

H-F> H-O> O-F

while H-H is nonpolar.

Explanation:

The bond is polar when electronegativity difference of both bonded atom is greater than 0.4.

Electronegativity values of O. F and H are

O = 3.4

H = 2.2

F = 3.98

For O-F

3.98 - 3.4 = 0.58

For H-F

3.98 - 2.2 = 1.78

For H-O

3.4 - 2.2 =  1.2

For H-H

2.2 -2.2 = 0

So H-H is nonpolar.

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A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h
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The ratio of f at the higher temperature to f at the lower temperature is 5.356

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Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]

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\frac{f_2}{f_1}  is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1}  = 10^{0.7289}\\\\\frac{f_2}{f_1}  = 5.356

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356

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