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lora16 [44]
3 years ago
7

33p is a radioactive isotope of phosphorus. can 33p be used to make a radioactive nucleotide?

Chemistry
2 answers:
Lunna [17]3 years ago
8 0
Yes, because it can replace the phosphorus atom in the phosphate group. Apex.
Agata [3.3K]3 years ago
5 0

Answer:

Yes, we can use 33p used in making radioactive nucleotide because phosphorus changes into phosphate group.

Explanation:

Phosphorus is the artificial radioactive element, mainly isotopes of Uranium and Polonium are used in making radioactive elements. 33p(Half life of 25.34 days) and 32p(Half life of 14.263 days) are the radioactive type of phosphorus.

Therefore, we can use 33p used in making radioactive nucleotide because phosphorus changes into phosphate group.            

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Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT
marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

(c) L(T, α) = 60·α·T - 9000·α + 60

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L =  L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

(c) L = L₀ + ΔL  = L₀ +  α × L₀ × ΔT = L₀ +  α × L₀ × (T - T₀)

Therefore;

L = 60 +  α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

7 0
3 years ago
1 point
inysia [295]

Answer:

The fungus has grown larger

Explanation:

Because where the orange is in the fridge and even normally you out oranges on the counter or in a bowl, where it's in the fridge it got old faster.

8 0
3 years ago
Amy is in a car moving quickly toward a stationary siren. Just as Amy moves
sineoko [7]

Answer:

Pitch

Explanation:

5 0
3 years ago
If you start with 4.3 moles of NH3, how many moles of NANH2 can be produced
mash [69]

Explanation:

Mole ratio of NH3 to NaNH2 = 2 : 2.

Moles of NaNH2 produced

= 4.3mol * (2/2) = 4.3mol.

4 0
3 years ago
How many electrons would a neutral atom of nitrogen need to gain in order to have a full valence electrons shell
Alexeev081 [22]
Nitrogen atom has a valence electrons of 5 electrons. A full octet or full valence electrons shell is composed of 8 electrons. Hence, an additional of 4 electrons are needed for it to become full. this is achieved by covalent bonding where electrons are shared or ionic bonding where electrons are transferred.
4 0
3 years ago
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