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lora16 [44]
3 years ago
7

33p is a radioactive isotope of phosphorus. can 33p be used to make a radioactive nucleotide?

Chemistry
2 answers:
Lunna [17]3 years ago
8 0
Yes, because it can replace the phosphorus atom in the phosphate group. Apex.
Agata [3.3K]3 years ago
5 0

Answer:

Yes, we can use 33p used in making radioactive nucleotide because phosphorus changes into phosphate group.

Explanation:

Phosphorus is the artificial radioactive element, mainly isotopes of Uranium and Polonium are used in making radioactive elements. 33p(Half life of 25.34 days) and 32p(Half life of 14.263 days) are the radioactive type of phosphorus.

Therefore, we can use 33p used in making radioactive nucleotide because phosphorus changes into phosphate group.            

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What is the concentration of H+ in 0.0025 M HClO4? What is the pH of the solution? What is the OH− concentration in the solution
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Answer:

A. The concentration of H+ is 0.0025 M

B. The pH is 2.6

C. The concentration of OH- is 3.98x10^-12 M

Explanation:

We'll begin by writing the balanced

dissociation equation of HClO4. This is illustrated below:

HClO4 —> H+ + ClO4-

A. Determination of the concentration of H+ in 0.0025 M HClO4. This is illustrated below:

From the balanced equation above,

1 mole of HClO4 produced 1 mole of H+.

Therefore, 0.0025 M of HClO4 will also produce 0.0025 M of H+.

The concentration of H+ is 0.0025 M

B. Determination of the pH.

The pH of the solution can be obtained as follow:

The concentration of H+, [H+]

= 0.0025 M

pH =?

pH = - log [H+]

pH = - log 0.0025

pH = 2.6

C. Determination of the concentration of OH-

To obtain the concentration of OH-, we must first calculate the pOH of the solution. This is illustrated below:

pH + pOH = 14

pH = 2.6

pOH =?

pH + pOH = 14

2.6 + pOH = 14

Collect like terms

pOH = 14 - 2.6

pOH = 11.4

Now, we can calculate the concentration of the OH- as follow:

pOH = - Log [OH-]

pOH = 11.4

11.4 = - Log [OH-]

- 11.4 = log [OH-]

[OH-] = anti log (- 11.4)

[OH-] = 3.98x10^-12 M

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