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Helga [31]
3 years ago
6

Which labels correctly identify the layers most closely associated with gamma rays and visible light? Z: Gamma rays X: Visible l

ight X: Gamma rays Z: Visible light Z: Gamma rays Y: Visible light Y: Gamma rays Z: Visible light
Physics
1 answer:
Marianna [84]3 years ago
4 0
The answer is Z: Gamma rays X: Visible light. Gamma ray is the shortest and has the greatest frequency and power. That is why it is in letter Z.
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A force of 99 N causes a box to accelerate at a rate of 12 m/s2. What is the mass of the box?
ira [324]


m = F/a

m = 99/11 = 9

The answer is 9 Kg

5 0
3 years ago
Label the sound wave-   amplitude, wavelength,  crest, trough​
enot [183]

Answer:

A - Crest,  B - amplitude,  C - wavelength,  D - trough

Explanation:

7 0
2 years ago
Helppppppppppppppp asappppppppppppp
vichka [17]
The answer to the problem b.
8 0
3 years ago
What is the formula of the compound between calcium and sulfur that has the percent composition 55.6?
Yanka [14]

CaS is the empirical formula of the compound between calcium and sulphur that has the percent composition 55.6.

When percentages are given, we take a total mass of 100 grams.

Therefore the mass of each element is equal to the percentage given.

Mass of Ca = 55.6 g (given) of

S Mass = 44.4 g (100 - 55.6 = 44.4)

Step 1: Convert the given mass to moles.

moles Ca = given mass Ca / molar mass Ca

moles = 55.6 / 40 = 1.39 moles

mol S = specific mass S / molar mass S

mol = 44.4 / 32 = 1.39 mol

Step 2: Divide the molar ratio of each molar value by the smallest number of moles calculated.

For Ca = 1.39 / 1.39 = 1

For S = 1.39 / 1.39 = 1

The ratio of Ca : S = 1:1

Hence the empirical formula of the given compound will be CaS.

Learn more about empirical formula here : brainly.com/question/1496676

#SPJ4

8 0
1 year ago
Two cars are traveling along perpendicular roads, car A at 40 mi/hr, car B at 60 mi/hr. At noon, when car A reaches the intersec
Serggg [28]

Answer:

\frac{dD}{dt} = -4 miles/hour

negative sign indicates that the distance is decreasing with time

Explanation:

Let at any time t after noon that is 12 p.m.  

distance traveled by car A = 40t

distance traveled by car B = 90-60t

then distance between the two cars at time t

D^2= (40t)^2+(90-60t)^2............1

also, at time 1 p.m.

distance D^2= (40\times1)^2+(90-60\times1)^2

D=50 Km

differentiating equation 1 w.r.t. t we get

2D\frac{dD}{dt}= 2\times40t\times40+2(90-60t)(-60)

put t= 1 and D= 50 we get

2\times50\frac{dD}{dt}= 3200\times1-3600\times1

\frac{dD}{dt} = -4 miles/hour

3 0
3 years ago
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