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3 years ago

What is the correct formula for finding the frequency of an electromagnetic wave

1 answer:

3 0

Answer:
f = c / λ

Explanation:
Electromagnetic waves are types of periodic waves. They propagate with the same speed as light (3 * 10⁸ m/sec).
Therefore:
velocity of wave = c

Now, the equation that relates speed of wave and its frequency is as follows:
c = λf
where:
c is the speed of wave
f is the frequency of the wave
λ is the wavelength of the wave

Solve the above equation for frequency, we will end up with:
f = c / λ

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Please help on this physics question?

Anton [14]

W=F*d

W=-60N*5m=-300J

So friction does -300J of work on the box

5 0

3 years ago

How much would you have to shrink a baseball to a black hole?

Vesna [10]

The Schwarzchild radius is . . . <em>R = 2GM/c² .</em>

Just like you, I'm not completely sure what that means. But it DOES use the mass of a black hole to calculate a radius associated with it, so with 15 Brainly points at stake, it seems like a good-enough formula to use for an answer.

Before I proceed, I really should ask you whether you're talking a softball or a hardball, but again . . . . .

So R = 2GM/c²

G = the gravitational constant = 6.67 x 10⁻¹¹ N-m²/kg²

M = mass of the baseball = 145 grams = 0.145 kg

c = speed of light = 3 x 10⁸ m/s

R = 2 (6.67 x 10⁻¹¹ m³/kg-s²) (0.145 kg) / (3 x 10⁸ m/s)²

R = (2 x 6.67 x 10⁻¹¹ x 0.145 / 9 x 10¹⁶) (m³-kg-s² / kg-s²-m²)

R = ( 1.9343 x 10⁻¹¹ / 9 x 10¹⁶) (m³-kg-s²/m²-kg-s²)

R = (0.2149 x 10⁻²⁷) meter

<em>R = 2.149 x 10⁻²⁸ meter</em>

For reference: The radius of a Hydrogen atom is 1.2 x 10⁻¹⁰ meter.

So in order to make a black hole out of a baseball, you have to crunch the baseball down to around 0.000000000000000001791 the size of a Hydrogen atom.

Would that be a problem for you ?

3 0

3 years ago

Technician A says that power is the rate that energy is stored. Technician B says that power refers to the rate that energy is t

Alex777 [14]

Answer:

C. Both technicians A and B

Explanation:

From the physical definition, power is defined as the rate of a body doing work. It is expressed as

P = w/t watts

Where

w - is the work done or the energy of the system in joules

t - time

The unit of power is represented in watts.

Whenever there is a rate of change of energy in the system, it accounts for the efficiency of the power of the system.

Hence, the statements of both technicians are correct.

7 0

4 years ago

A mechanic pushes a 2.30 ✕ 103-kg car from rest to a speed of v, doing 4,800 J of work in the process. During this time, the car

Illusion [34]

The horizontal force applied is 160 N while the velocity is 2.03 m/s.

<h3>What is the speed of the car?</h3>

The work done by the car is obtained as the product of the force and the distance;

W = F x

F = ?

x = 30.0 m

W = 4,800 J

F = 4,800 J/30.0 m

F = 160 N

But F = ma

a = F/m

a = 160 N/2.30 ✕ 10^3-kg

a= 0.069 m/s

Now;

v^2 = u^2 + 2as

u = 0/ms because the car started from rest

v = √2as

v = √2 * 0.069 * 30

v = 2.03 m/s

Learn more about force and work:brainly.com/question/758238

#SPJ1

5 0

2 years ago

point A is at the bottom of a rough plane which is inclined at angle tita to the horizontal . A body of mass M is projected from

ziro4ka [17]

<h2>The work done , when body moves along the plane </h2>

Explanation:

A body is projected from bottom of the inclined plane . When body is going up the plane .

The downward force = m g sinθ is developed due to its weight

As body is moving upwards , the force of friction will act downwards

The force of friction = μ R

here μ is the coefficient of friction ans R is the normal reaction

Thus force of friction f = μ mg cosθ

Let the acceleration upwards is a

The upward force required = m a

Thus m a = mg sinθ + μ mg cosθ

or acceleration a = g ( sinθ + μ cosθ )

The work done in moving upwards W = F S

Thus W = mg ( sinθ + μ cosθ ) S

here S is the displacement on the plane

When body moves down , the force of friction acts upwards

Thus m a = m g ( sinθ - μ cosθ )

The work done W = m g ( sinθ - μ cosθ ) S

As the body is projected with velocity u

which can be calculated by the relation v² - u² = - 2 a X

Here v = 0 at the highest point

Thus u = $\sqrt{2ax}$

here a = g ( sinθ + μ cosθ )

Similarly , when it moves down , the initial velocity u = 0

Thus v² - 0 = 2 a x

or v = $\sqrt{2ax}$

here a = g ( sinθ - μ cosθ )

3 0

3 years ago