1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zolol [24]
3 years ago
12

A spring with spring constant of 34 N/m is stretched 0.12 m from its equilibrium position. How much work must be done to stretch

it an additional 0.062 m
Physics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:0.253Joules

Explanation:

First, we will calculate the force required to stretch the string. According to Hooke's law, the force applied to an elastic material or string is directly proportional to its extension.

F = ke where;

F is the force

k is spring constant = 34N/m

e is the extension = 0.12m

F = 34× 0.12 = 4.08N

To get work done,

Work is said to be done if the force applied to an object cause the body to move a distance from its initial position.

Work done = Force × Distance

Since F = 4.08m, distance = 0.062m

Work done = 4.08 × 0.062

Work done = 0.253Joules

Therefore, work done to stretch the string to an additional 0.062 m distance is 0.253Joules

You might be interested in
NEED ASAP PLEASE
miskamm [114]

Given that the block have two applied masses 250 g at East and 100 g at South. In order to make a situation in which block moves towards point A, we have to apply minimum number of masses to the blocks. In order to prevent block moving toward East, we have to apply a mass at West, equal to the magnitude of mass at East but opposite in direction. Therefore, mass of 250 g at West is the required additional mass that has to be added. There is already 100 g of mass acting at South, that will attract block towards South or point A. No need to add further mass in North-South direction.

6 0
2 years ago
A brass alloy is known to have a yield strength of 240 MPa (35,000 psi), a tensile strength of 310 MPa (45,000 psi), and an elas
Karo-lina-s [1.5K]

Answer:

Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

Explanation:

Given that

Yield strength ,Sy= 240 MPa

Tensile strength = 310 MPa

Elastic modulus ,E= 110 GPa

L=380 mm

ΔL = 1.9 mm

Lets find strain:

Case 1 :

Strain due to elongation (testing)

ε = ΔL/L

ε = 1.9/380

ε = 0.005

Case 2 :

Strain due to yielding

\varepsilon' =\dfrac{S_y}{E}

\varepsilon' =\dfrac{240}{110\times 1000}

ε '=0.0021

Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

For computation of load strain due to testing should be less than the strain due to yielding.

4 0
3 years ago
When U-235 splits, it usually emits
Serga [27]
Splitting<span> atoms. 'Fission' is another word for </span>splitting<span>. The process of </span>splitting<span> a nucleus is called nuclear fission. ... For fission to happen, the </span>uranium-235<span> or plutonium-239 nucleus must first absorb a neutron.</span>
5 0
3 years ago
What actions can be explained by physics?
Vesna [10]
Всяко действие има равно по големина и противоположно по посока противодействие.
7 0
3 years ago
When dots are placed on a page from a laser printer, they must be close enough so that you do not see the individual dots of ink
Dovator [93]

Answer:

 y <8 10⁻⁶ m

Explanation:

For this exercise, they indicate that we use the Raleigh criterion that establishes that two luminous objects are separated when the maximum diffraction of one of them coincides with the first minimum of the other.

 Therefore the diffraction equation for slits with m = 1 remains

             a sin θ = λ

in general these experiments occur for oblique angles so

             sin θ = θ

             θ = λ / a

in the case of circular openings we must use polar coordinates to solve the problem, the solution includes a numerical constant

           θ = 1.22 λ / a

The angles in these measurements are taken in radians, therefore

          θ = s / R

as the angle is small the arc approaches the distance s = y

          y / R = 1.22 λ / s

          y = 1.22 λ R / a

let's calculate

            y = 1.22 500 10⁻⁹ 0.42 / 0.032

            y = 8 10⁻⁶ m

with this separation the points are resolved according to the Raleigh criterion, so that it is not resolved (separated)

                 y <8 10⁻⁶ m

4 0
3 years ago
Other questions:
  • You can painlessly wade into a pool, but doing a belly flop off of the high diving board hurts because of
    11·1 answer
  • To ensure the greatest nutritional benefits, dietary guidelines suggest which of the following?
    10·2 answers
  • A solenoid of length 18 cm consists of closely spaced coils of wire wrapped tightly around a wooden core. The magnetic field str
    8·1 answer
  • If the diameter of each of a car's wheels is 0.4 meters, approximately, what was the average speed of the car for its three-hour
    5·2 answers
  • A tsunami originatig near the Alaska coast had a wavelength of 470 miles and traveled 2300 miles in 5.3 h. Determine the wave’s
    10·1 answer
  • A florescent light tube usually contains what?
    7·1 answer
  • George walks to a friend's house. He walks 750 meters North, then realizes he walked
    9·1 answer
  • Vector of magnitude 15 is added to a vector of magnitude 25. The magnitude of this sum
    6·1 answer
  • A 5 kg object moving to the right at 4 m/s collides inelastically with a 5 kg object
    12·1 answer
  • A volleyball that has an initial momentum of
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!