Answer:
Explanation:
given volume =5.3 litres
as we know that 1 litre =1 dm3
therefore 5.3 litres =5.3 dm3
now moles =given mass /molar mass
so mass =moles*molar mass
in order to find mass of carbon we need to find moles
therefore moles=given volume/standard volume standard volume at STP is 22.4 dm3
moles= 5.3/22.4
moles=0.236=0.24
now mass of carbon dioxide =moles*molar mass
mass = 0.24*44
mass=10.56kg
Answer:
H-O-H polar
O-C-O nonpolar
H-C-N polar
Explanation:
Looking up the electronegativities of the atoms involved in this question, we have:
Atom Electronegativity
H 2.2
C 2.55
N 3.04
O 3.44
All of the atoms differ in electronegativity resulting in individual dipole moments in H-O, O-C, H-C and C-N bonds. To find if the molecules will be polar we need to consider the structure of the compound to see if there is a resultant dipole moment.
In H-O-H, we have 2 lone pairs of electrons around the central oxygen atom which push the angle H-O-H of the ideal tetrahedral structure to be smaller than 109.5 º resulting in an overall dipole moment making it polar.
In O-C-O, we have two dipole moments that exactly cancel each other in the linear molecule since the central carbon atom does not have lone pairs of electrons since it has 2 double bonds. Therefore the molecule is nonpolar.
In H-C-N, again we have have a central carbon atom without lone pairs of electrons and the shape of the molecule is linear. But, now we have that the dipole moment in C-N is stronger than the H-C dipole because of the difference in electronegativity of nitrogen compared to hydrogen. The molecule has an overall dipole moment and it is polar.
Answer:
45.2 mL must be meausred for the experiment
Explanation:
The density of the acetic acid is 1.105 g/mL, so this data gives the information about how many grams are contained in 1mL of volume.
Notice that 1 mL = 1 cm³
Acetic acid Density = Acetic acid mass / acetic acid volume
1.105 g/mL = 50 g / acetic acid volume
Acetic acid volume = 50 g / 1.105g/mL ⇒ 42.5 mL