Question

What is the molarity of a solution of 14.0 g NH4Br in enough H20 to make 150 mL of solution?

Answer 1

Mass of solute = 14,0 g

Molar mass ( NH4Br ) = 14 + 1 . 4 + 80 = 98 g/mol-1

volume of the solution = 150 mL  = 0,15 L

Molarity of the solution = mol/L-1

$M = \frac{m}{mm.V}$

$M = \frac{14,0}{98.0,15}$

$M = \frac{14,0}{14,7}$

$M = 0,952 mol/L ^{-1}$


Hope this helps!