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netineya [11]
3 years ago
9

What is the acceleration if we speed up from 10m/s to 30 m/s in 10 seconds

Physics
1 answer:
lina2011 [118]3 years ago
3 0
Acceleration= change in speed/ change in time

30-10= 20 (change in speed)
Time= 10 seconds

20/10= 2
Acceleration= 2 m/s^2

Hope this helps! :)
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Three disks are spinning independently on the same axle without friction. Their respective rotational inertias and angular speed
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Answer:

3/7 ω

Explanation:

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I(-ω) + (2I)(3ω) + (4I)(-ω/2) = (I + 2I + 4I) ωnet

-Iω + 6Iω - 2Iω = 7I ωnet

3Iω = 7I ωnet

ωnet = 3/7 ω

The final angular velocity will be 3/7 ω counterclockwise.

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Sunglasses that reduce glare take advantage of which kind of wave
marysya [2.9K]

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It should be option B polarization

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Based on their colors, which of the following stars is hottest? Which is coolest? Archenar (blue), Betelgeuse (red), Capella (ye
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Answer: The hottest star is Archenar( blue) and the coolest star is Betelgeuse

Explanation:

Objects emit radiation that depends exclusively on their temperature. At an ambient temperature, the radiation emitted by an object is in the infrared spectrum (we could only see it with a special camera). If we heat it we will see that it first turns red (whose state we call “red hot”) because it is the lowest and least energetic wavelength of all.

If we continue to heat it, the wavelength that it emits to one with more energy will continue to increase and we will see that it turns yellow and then white. This is a signal that is emitting at all frequencies (but mainly in blue).

If we continue to warm a body that is "white hot", it would emit in the ultraviolet spectrum, with what would become ... black! then we would not see it emits light in the visible spectrum (well, we would see a very faint bluish light corresponding to the tail of the distribution of the spectrum it emits, but the peak of that spectrum would be in the ultraviolet).

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3 years ago
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On a straight, level, two-lane road, two cars moving in opposite directions approach and pass each other. Car A is in the eastbo
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a) 42 m/s, positive direction (to the east), b) 42 m/s, negative direction (to the west).

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42 m/s, positive direction (to the east).

b) The relative velocity of Car B as seen by the drive of Car A is:

\vec v_{B/A} = \vec v_{B} - \vec v_{A}\\\vec v_{B/A} = -31 \frac{m}{s} \cdot i - 11 \frac{m}{s} \cdot i\\\vec v_{B/A} = - 42 \frac{m}{s} \cdot i

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Is friction and pushing similar ????
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Yes, they are.

Explanation:

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