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m_a_m_a [10]
3 years ago
9

. ______________ will slow down alcohol absorption. Sleeping well Food in the large intestine Being happy and relaxed Food in th

e stomach that is high in protein
Chemistry
1 answer:
solong [7]3 years ago
7 0

Answer:

Food in the stomach that is high in protein will dilute absorption of alcohol in your stomach :) therefore always drink with food in your stomach, just drinking alchol without food will have serious consequences on helath.

Explanation:

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3. The substance that is formed or we finish up with are called.​
skad [1K]
Products. I’m not 100% sure because I don’t fully understand what your asking but if you are talking as in chemical reactions, the answer is a product.
6 0
2 years ago
the mass of a 125 cm3 piece of material is 82.75 g. determine the density of this material . please explain
andre [41]
You would do 82.75 divided by 125 cm3 and get 0.6620 g/cm3 because to find density you mist divide mass and volume and grams is always mass and cm3 or mL is always volume. hope i helped!
6 0
3 years ago
Why do atoms form blonds​
lakkis [162]

Answer:

Atoms form chemical bonds to make their outer electron shells more stable. ... An ionic bond, where one atom essentially donates an electron to another, forms when one atom becomes stable by losing its outer electrons and the other atoms become stable (usually by filling its valence shell) by gaining the electrons.

Explanation:

7 0
3 years ago
In a thin layer chromatography experiment, a plate of length 9.3 cm was used and a horizontal line was made at 1.45 cm above the
dezoksy [38]

Answer: The R_f value is 0.664

Explanation:

Distance travelled by solvent front = (7.7-1.45)cm = 6.25 cm

Distance travelled by unknown = (5.6-1.45) cm = 4.15 cm

 The retention factor or the R_f value is defined as the ratio of distance traveled by the unknown to the distance traveled by the solvent front.

R_f=\frac{\text {distance travelled by unknown}}{\text {distance travelled by solvent}}

R_f=\frac{4.15}{6.25}=0.664

Thus the R_f value is 0.664

6 0
2 years ago
Calculate the mass of CO2 that can be produced if the reaction of 54.0 g of propane and sufficient oxygen has a 64.0% yield.
Oduvanchick [21]

Answer:

103.9 g

Explanation:

  • C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

First <u>we convert 54.0 g of propane (C₃H₈) into moles</u>, using its <em>molar mass</em>:

  • 54.0 g ÷ 44 g/mol = 1.23 mol C₃H₈

Then we <u>convert 1.23 moles of C₃H₈ into moles of CO₂</u>, using the <em>stoichiometric coefficients</em>:

  • 1.23 mol C₃H₈ * \frac{3molCO_2}{1molC_3H_8} = 3.69 mol CO₂

We <u>convert 3.69 moles of CO₂ into grams</u>, using its <em>molar mass</em>:

  • 3.69 mol CO₂ * 44 g/mol = 162.36 g

And <u>apply the given yield</u>:

  • 162.36 g * 64.0/100 = 103.9 g
7 0
2 years ago
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