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Anastasy [175]
3 years ago
15

Two laws are described below:

Physics
2 answers:
taurus [48]3 years ago
8 0

Answer:

i beleive the answer is  B Both Law A and Law B are scientific laws.

Explanation:

liubo4ka [24]3 years ago
3 0

Answer:

Explanation:

I can conclude that this means that the law can be broken under certain coditions as long as its not focused on a natural phenomonon

and a pheononmono is a fact or situation that is observed to exist or happen, especially one whose cause or explanation is in question.

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What is the momentum of a 750 kg car traveling at a velocity of 25 m/s north?
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18750 kg-m/s

Explanation:

Momentum = mass x velocity 

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___ acceleration occurs when an object speeds up
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Explanation:

Acceleration is defined as the change in velocity over time.

When there is an increment or increase in the magnitude of velocity of a moving body then it is known as positive acceleration.

Whereas when there is a decrease in magnitude of velocity of a moving body then it is known as negative acceleration.

Thus, we can conclude that positive acceleration occurs when an object speeds up.

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If a weight hanging on a string of length 5 feet swings through 5^\circ on either side of the vertical, how long is the arc thro
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<span>First we can find the circumference of the whole circle with a radius of 5 feet. circumference = 2 pi radius circumference = (2 pi) (5 feet) circumference = (10 pi) feet From one high point to the other high point, the string moves through an angle of 10 degrees. Since a full circle is 360 degrees, this angle is 1/36 of a full circle. Therefore, the arc length is 1/36 of the whole circumference. arc length = (1/36) (circumference) arc length = (1/36) (10 pi) feet arc length = 0.873 feet</span>
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What is the name of the hair-like structures on sponge cells that move back and forth to help move water, nutrients, and waste t
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What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 22 km/h and the coef
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First, let's put 22 km/h in m/s:

22 \frac{km}{h} \times  \frac{1000m}{1km}  \times  \frac{1h}{3600s}=6.11 \frac{m}{s}

Now the radial force required to keep an object of mass m, moving in circular motion around a radius R, is given by

F_{rad}=m \frac{v^2}{R}

The force of friction is given by the normal force (here, just the weight, mg) times the static coefficient of friction:

F_{fric}= mg \mu_{s}

Notice we don't use the kinetic coefficient even though the bike is moving.  This is because when the tires meet the road they are momentarily stationary with the road surface.  Otherwise the bike is skidding.

Now set these equal, since friction is the only thing providing the ability to accelerate (turn) without skidding off the road in a line tangent to the curve:

m\frac{v^2}{R} = mg \mu_{s} \\ \\ \frac{v^2}{R} = g \mu_{s} \\ \\R= \frac{v^2}{g \mu_{s}} \\ \\ R= \frac{6.11}{9.8 \times 0.37}=1.685m

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3 years ago
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