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krek1111 [17]
3 years ago
14

A child whose weight is 235 N slides down a 4.90 m playground slide that makes an angle of 37.0° with the horizontal. The coeffi

cient of kinetic friction between slide and child is 0.0510. (a) How much energy is transferred to thermal energy? (b) If she starts at the top with a speed of 0.355 m/s, what is her speed at the bottom?
Physics
1 answer:
Basile [38]3 years ago
7 0

Answer:

Explanation:

a) First, let's calculate the value of the Friction force, which is given by the formula:

Ff = u*W

As the Friction force has an X component, it would be:

Ff = u*m*g*cosФ

Where m*g is the weight of the child.

Solving for Ff:

Ff = 0.051 * 235cos37 = 9.57 N

Now, to get the energy transferred to thermal energy (or heat) we need to get the Work done, so:

Wf = Ff * d

Wf = 9.57 * 4.9 = 46.9 J

b) We need to get the downslope component of the child weight, which is:

Wy = 235sin37 = 141.43 N

As you can imagine, the gravity also does work, so:

Wg = Wy * d

Wg = 141.43 * 4.9 = 693 J

Now, let's get the kinetic energy, which can be obtained by this expression:

ΔKe = Wg - Wf

ΔKe = 693 - 46.9 = 646.1 J

The formula for kinetic energy is:

Ke = 1/2 m*V^2

We have the innitial speed which is 0.355 m/s, and the mass can be obtained by m*g so:

Fw= m*g ----> m = Fw/g

m = 235 / 9.8 = 23.97 kg

so the innitial energy is:

Ke = 1/2 * 23.97 * (0.355)^2

Ke = 1.51 J

This could be Ke1, so to get Ke2:

ΔKe = Ke2 - Ke1

Ke2 = Δke + Ke1

Ke2 = 646.1 + 1.51 = 647,61 J

Finally, the speed at the bottom would be:

v = √2Ke/m

v = √2*647.61/23.97

v = 7.35 m/s

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Approximately how much electrical energy does a 5-W lightbulb convert to radiant and thermal energy in one hour?​
k0ka [10]

Answer:

18,000 j

Explanation:

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rearrange to solve for energy

ΔE = PΔt

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8 0
3 years ago
Help please I'm struggling.
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3 years ago
You are at the park with your little brother, when you notice a small merry-go-round with a radius that looks to be about 1.5 m.
Elodia [21]

Answer:

Explanation:

angle covered in one rotation = 2π radian

θ = ωt + 1/2 αt²

θ is angle rotated in time t with initial angular velocity of ω and angular acceleration α .

Putting the values

2π = 0 + 1/2 x α x 3²

α = 1. 4 radian / s²

linear acceleration =  α x r = 1.4 x 1.5 = 2.1 m / s².

Initial acceleration = 2.1 m /s²

final angular velocity = α t = 1.4 x 3 = 4.2 radian / s

linear velocity = 4.2 x 1.5 = 6.3 m /s

centripetal acceleration = v² / R = 6.3² / 1.5 = 26.46 m /s²

radian acceleration = 26.46 m /s

tangential acceleration = 2.1 m /s²

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3 years ago
What is her displacement
Aleks04 [339]

Answer:

c) 2 blocks

Explanation:

Her displacement is the difference between her starting point and her ending point.

Let's say she starts at the origin, (0, 0).

First, she goes 13 blocks east: (13, 0)

Next, she goes 4 blocks north: (13, 4)

Then she goes 8 blocks west: (5, 4)

Then she goes 6 blocks south: (5, -2)

Finally, she goes 5 blocks west: (0, -2)

The magnitude of her displacement is the distance between her initial and final positions: 2 blocks.

8 0
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