Answer:
8.46 N/C
Explanation:
Using Gauss law

Gauss's Law states that the electric flux through a surface is proportional to the net charge in the surface, and that the electric field E of a point charge Q at a distance r from the charge
Here, K is Coulomb's constant whose value is 
r = 0.43 + 0.106 = 0.536 m

Both masses will have the same acceleration. The cart accelerates to the right with a magnitude of 4.9 m/
. The correct answer is 4.90 m/
Given that a massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface.
Let M = 1kg and m = 3 kg
Since the horizontal surface is frictionless, the tension in the string will be the same. when the mass is hanged over a frictionless pulley, the tension will also be the same.
When the mass is released, the cart accelerates to the right can be calculated from Newton' second law of motion. That is,
M( g + a) = m(g - a)
1(9.8 + a) = 3( 9.8 - a)
9.8 +a = 29.4 - 3a
collect the like terms
4a = 19.6
a = 19.6/4
a = 4.9 m/
Therefore, the cart accelerates to the right with a magnitude of 4.9 m/
. The correct answer is 4.90 m/
Learn more about dynamics here: brainly.com/question/24994188
Each orbit is approximately 365.24 days ... the period we call a "year".
Four of those = 1,461 days = 4 years .