1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alenkinab [10]
3 years ago
6

Question 3 You see the coordinates 5 E longitude, 10 N latitude. You do not need to look at a map in order to deduce that this l

ocation is a. near both the equator and the prime meridian Selected: b. near the International Date Line as well as the North PoleThis answer is incorrect. c. near the International Date Line and the prime meridian d. near the equator but quite far from the prime meridian e. near both the equator and the International Date Line
Physics
2 answers:
olchik [2.2K]3 years ago
8 0

Answer:

a. near both the equator and the prime meridian

Explanation:

Lets first understand what is equator and prime meridian.

We have drawn an imaginary grid on the Earth for navigational and other purposes. This grid has two coordinates : Latitude and Longitude. Equator is the largest latitude circle that divides the Earth in two equal hemispheres. This is taken as 0° for latitude. Latitudes increase as we move towards North/South pole which lies at 90°N and 90° S respectively. Longitudes are the lines running from north pole to south pole. The longitude that crosses from Greenwich is taken as 0°. This longitude is also known as prime meridian. The value of longitudes vary from 0° to 180° East and 180° West.

Now, the given coordinates are: 5° E and 10° N. It is quite evident that this location will be close to equator and prime meridian.

san4es73 [151]3 years ago
5 0

Answer:

a. Near both the equator and the prime meridian.

Explanation:

The  equator is at 0 degrees latitude and the prime meridian is 0 degrees longitude.

You might be interested in
Derive an expression for the gravitational potential energy U(r) of the object-earth system as a function of the object's distan
Drupady [299]

Answer:

U(r)=-\frac{Gm_Emr^2}{2R^3_E}

Explanation:

We are given that

Gravitational force=F_g=\frac{Gm_Emr}{R^3_E}

r=0,U(0)=0

We know that

Gravitational potential energy=-\int F_gdr

U(r)=-\int\frac{Gm_Emr}{R^3_E}dr

U(r)=-\frac{Gm_Em}{R^3_E}\times \frac{r^2}{2}+C

Substitute r=0 ,U(0)=0

0=0+C

C=0

Substitute the value

U(r)=-\frac{Gm_Emr^2}{2R^3_E}

4 0
3 years ago
Choose all the answers that apply. Which of the following statements are true? Science is always a positive force. Animal testin
Ilya [14]
<span>Skepticism is a quality that scientists need. Because if they do not have that, they would not be motivated to do research on things they have doubts on. We would not have things we have today. Please rate me, and if this helped, thank me. If this really helped crown me brainiest answer.  </span>
4 0
3 years ago
Which statement describes the relationship between bond strength and the melting and boiling points of a substance? A. As the fo
icang [17]

Answer:

a

Explanation:

4 0
3 years ago
Are worm holes a real phenomenon?
Katena32 [7]
It depends, because worm holes are theoretical construed of space and time. It hasn’t been proven to exist but mathematically it hasn’t been spotted but we also haven’t been very far in our universe.

So to cut the story short, it is not a proven phenomenon only theoretical.
6 0
4 years ago
Read 2 more answers
You are the juror of a case involving a drunken driver whose 1041 kg sports car ran into a stationary 1928 kg station wagon stop
mina [271]
1. Find the force of friction between the sports car and the station wagon stuck together and the road. The total mass m = 1928kg + 1041kg = 2969kg. The only force in the x-direction is friction: F = μ*N = μ * m * g 
2. Find the acceleration due to friction: 
F = m*a =  μ * m * g => a = μ * g = 0.6 * 9.81
3. Find the time it took the two cars stuck together to slide 12m:
x = 0.5*a*t² 
t = sqrt(2*x / a) = sqrt(2 * x / (μ * g) )
4. Find the initial velocity of the two cars:
v = a*t = μ * g * sqrt(2 * x / (μ * g) ) = sqrt( 2 * x * μ * g)
5. Use the initial velocity of the two cars combined to find the velocity of the sports car. Momentum must be conserved:

m₁ mass of sports car
v₁ velocity of sports car before the crash
m₂ mass of station wagon
v₂ velocity of station wagon before the crash = 0
v velocity after the crash

m₁*v₁ + m₂*v₂ = (m₁+m₂) * v = m₁*v₁ 
v₁ = (m₁+m₂) * v / m₁ = (m₁+m₂) * sqrt( 2 * x * μ * g) / m₁
v₁ = 33.9 m/s


7 0
3 years ago
Other questions:
  • In a given city, the permissible limit of CO (carbon monoxide) in the air is 100 parts per million (ppm). The city monitors the
    8·2 answers
  • Which condition must be met in order for an equation to be balanced?
    7·1 answer
  • A 15 kg mass is moving at 7.50 meters per second on a horizontal, frictionless surface. What is the total work that must be done
    12·1 answer
  • Which two options are examples of waves reflecting?
    6·1 answer
  • Wire A has the same length and twice the radius of wire B. Both wires are made of the same material and carry the same current.
    8·1 answer
  • What does x represent on a motion in physics
    14·1 answer
  • Explain Rutherford's experiment?
    10·1 answer
  • Which of the following statements is true of electromagnetic waves but NOT mechanical waves.
    10·1 answer
  • A ball is dropped off a building and falls past a window that is 2.2m long. If it takes .28s for the ball to cross the window wh
    15·1 answer
  • A red light means to stop. If you are turning from a two-way road or onto a two-way road, then you are NOT allowed to turn
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!