Answer:
velocity of car=5.855 m/s
Explanation:
Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The magnitude is
, the direction is into the page
Explanation:
From the question we are told that
The current is 
The radius of arc bc is 
The radius of arc da is 
The length of segment cd and ab is = 
The objective of the solution is to obtain the magnetic field
Generally magnetic due to the current flowing in the arc is mathematically represented as
Here I is the current
is the permeability of free space with a value of 
r is the distance
Considering Arc da

Where
is the angle the arc da makes with the center from the diagram its value is 
Now substituting values into formula for magnetic field for da
![B_{da} = \frac{4\p *10^{-7} * 12}{4 \pi (0.20)}[\frac{2 \pi}{3} ]](https://tex.z-dn.net/?f=B_%7Bda%7D%20%3D%20%5Cfrac%7B4%5Cp%20%2A10%5E%7B-7%7D%20%2A%2012%7D%7B4%20%5Cpi%20%280.20%29%7D%5B%5Cfrac%7B2%20%5Cpi%7D%7B3%7D%20%5D)
![= \frac{10^{-7} * 12}{0.20} * [\frac{2 \pi}{3} ]](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B10%5E%7B-7%7D%20%2A%2012%7D%7B0.20%7D%20%2A%20%5B%5Cfrac%7B2%20%5Cpi%7D%7B3%7D%20%5D)

Looking at the diagram to obtain the direction of the current and using right hand rule then we would obtain the the direction of magnetic field due to da is into the pages of the paper
Considering Arc bc

Substituting value
![B_{bc} = \frac{4 \pi *10^{-7} * 12}{4 \pi (0.30)} [\frac{2 \pi}{3} ]](https://tex.z-dn.net/?f=B_%7Bbc%7D%20%3D%20%5Cfrac%7B4%20%5Cpi%20%2A10%5E%7B-7%7D%20%2A%2012%7D%7B4%20%5Cpi%20%280.30%29%7D%20%5B%5Cfrac%7B2%20%5Cpi%7D%7B3%7D%20%5D)

Looking at the diagram to obtain the direction of the current and using right hand rule then we would obtain the the direction of magnetic field due to bc is out of the pages of the paper
Since the line joining P to segment bc and da makes angle = 0°
Then the net magnetic field would be



Since
then the direction of the net charge would be into the page
I’m sure it’s called a circuit:)
10 joules of work is done by the object